There is not enough information to answer the question. The answer depends onis the object travelling at constant velocity?is the acceleration constant?If it is an object travelling with constant acceleration, which three of the following four variables are knows: initaial velocity, final velocity, acceleration and time.
d(t)=Vi(t)+((1/2)(a*t^2)) I just can't find anywhere to explain where that 1/2 constant comes from.
If starting from rest, Distance = 1/2 (acceleration) x (time)2 . Otherwise, Distance = 1/2 (initial speed + final speed) x (time)
distance traveled = speed multiplied by time taken.
Assuming that the car moves at a constant speed, you can use the standard formula for speed: distance = speed x time
The distance traveled would depend on the spacecraft's speed and the escape velocity of the planet. The formula to calculate the distance traveled with constant acceleration is D = (1/2)at^2, where D is distance, a is acceleration, and t is time. By plugging in the values, you can find the distance traveled.
Acceleration=Speed1-speed2/Distance traveled
There is not enough information to answer the question. The answer depends onis the object travelling at constant velocity?is the acceleration constant?If it is an object travelling with constant acceleration, which three of the following four variables are knows: initaial velocity, final velocity, acceleration and time.
For objects falling under constant acceleration (such as gravity), the distance an object travels each second is determined by the formula d = 0.5 * a * t^2, where "d" is the distance, "a" is the acceleration, and "t" is the time in seconds. This means that the distance traveled each second will increase quadratically as time passes.
You can use the equation: distance = (initial velocity + final velocity) / 2 * time. This formula assumes constant acceleration.
The formula for speed is speed = distance / time, where speed is measured in m/s or km/h. The formula for acceleration is acceleration = change in velocity / time taken, where acceleration is measured in m/sĀ².
d(t)=Vi(t)+((1/2)(a*t^2)) I just can't find anywhere to explain where that 1/2 constant comes from.
If starting from rest, Distance = 1/2 (acceleration) x (time)2 . Otherwise, Distance = 1/2 (initial speed + final speed) x (time)
Acceleration = 0 Speed = constant Distance = (speed) x (time)
Time affects the distance traveled by an object in motion through the formula distance = speed x time. The longer the time, the greater the distance traveled if the speed remains constant. Conversely, if the time is decreased, the distance traveled will also be less if the speed remains constant.
Distance traveled can be calculated using the formula: distance = 0.5 * acceleration * time^2, where acceleration = force / mass. First, calculate acceleration by dividing the force by the mass, then plug the acceleration value into the formula along with the time to find the distance traveled.
distance traveled = speed multiplied by time taken.