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If an object is accelerating what equation relates the distance traveled by that object to the initial velocity final velocity and time?
The equation that relates the distance traveled by a constantly accelerating object to its initial velocity, final velocity, and time is the equation of motion: [ \text{distance} = \frac{1}{2} \times (\text{initial velocity} + \text{final velocity}) \times \text{time} ] This equation assumes constant acceleration.
How do you find distance with uniform velocity time final velocity and initial velocity?
If the velocity is uniform, then the final velocity and the initial velocity are the same. Perhaps you meant to say uniform acceleration. In any event, the question needs to be stated more precisely.
When is acceleration equals half of the sum of initial and final velocities?
Acceleration is equal to half the sum of initial and final velocities at the midpoint of the motion when the acceleration is constant. This occurs when the object has undergone half of the acceleration time and traveled half of the distance between initial and final velocities.
How do you find displacement when you only have acceleration initial velocity and final velocity?
You can use the equation: Displacement = (final velocity squared - initial velocity squared) / (2 * acceleration). Plug in the values of final velocity, initial velocity, and acceleration to calculate the displacement.
How do you find distance with final velocity and minimum acceleration?
To find the distance using final velocity and minimum acceleration, you can use the formula: distance = (final velocity)^2 / (2 * acceleration). Simply square the final velocity, then divide by 2 times the minimum acceleration to get the distance traveled.
If an object is accelerating what equation relates the distance traveled by that object to the initial velocity final velocity and time?
The equation that relates the distance traveled by a constantly accelerating object to its initial velocity, final velocity, and time is the equation of motion: [ \text{distance} = \frac{1}{2} \times (\text{initial velocity} + \text{final velocity}) \times \text{time} ] This equation assumes constant acceleration.
What does initial velocity squared plus 2 times acceleration times distance equal?
This equation represents the final velocity squared when an object is accelerating from an initial velocity over a certain distance. It is derived from the kinematic equation (v^2 = u^2 + 2as), where (v) is the final velocity, (u) is the initial velocity, (a) is the acceleration, and (s) is the distance traveled.
How do you find the initial velocity given only the distance and the time traveled?
You can't. You need either the final velocity or the acceleration of the object as well, and then you can substitute the known values into a kinematics equation to get the initial velocity.
How do you find the distance if only the final velocity and the acceleration is given?
You can find the distance using the equation: distance = (final velocity)^2 / (2 * acceleration). Square the final velocity, divide it by twice the acceleration to get the distance traveled before coming to a stop.
How far does a plane fly in 15 seconds while its velocity is increasing from 75 miles per second to 145 miles per second at a uniform rate of acceleration?
To find the distance traveled, we can use the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. The initial velocity is 75 miles per second, the final velocity is 145 miles per second, and the time is 15 seconds. The acceleration can be found using the formula: acceleration = (final velocity - initial velocity) / time. Plug in the values to find the acceleration and then calculate the distance traveled in 15 seconds.
How do you find a final velocity without distance but given time?
Without distance, you have to know time, initial velocity, and acceleration, in order to find final velocity.
How do you find the final velocity given only distancetimeand initial velocity?
v = 2s/t - u where u=initial velocity, v=final velocity, s = distance and t = time
A speed bike tops a hill at 3.50 ms an accelerates steadily down the hill until reaching a speed of 11.4 ms after 4.20 second how far did the bike travel durig this period?
You can find the distance traveled by the bike by using the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. In this case, the initial velocity is 3.50 m/s, the final velocity is 11.4 m/s, the time is 4.20 seconds, and since the bike is accelerating, you can find the acceleration using the equation: acceleration = (final velocity - initial velocity) / time. Plug these values into the formula to find the distance traveled.
How do you find distance with uniform velocity time final velocity and initial velocity?
If the velocity is uniform, then the final velocity and the initial velocity are the same. Perhaps you meant to say uniform acceleration. In any event, the question needs to be stated more precisely.
If you know the acceleration of a car its initial velocity the time interval what can you predict?
Its final velocity, the distance covered.
What distance did the vehicle traveling at 13m travel before it stopped if it took the vehicle 5 seconds to stop?
To find the distance traveled before stopping, we can use the equation of motion: distance = initial velocity * time + 0.5 * acceleration * time^2. Since the final velocity is 0 m/s, the distance traveled is 13m/s * 5s = 65 meters.
How do you find final and initial velocity?
You use the information you're given, along with the equations and formulas you know that express some kind of relationship between the information you're given and the initial and final velocity.
