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However, assuming your question to find the roots or solutions of ax2 + bx + c = 0,
the answer is
x = [-b ± sqrt(b2 - 4ac)]/2a
b2 - 4ac is called the discriminant.
If the discriminant > 0 then the quadratic equation has two distinct real roots.
If the discriminant = 0 then the quadratic equation has one double root.
If the discriminant < 0 then the quadratic equation has two distinct complex roots that are conjugates of one another.
With a formula, you know the variable's value, and you have to calculate the value of the function of it. With an equation, you know the function's value, and you have to calculate the value of the variable.
dunctions are not set equal to a value
Using the discriminant formula for a quadratic equation k has a value of 8/25 or maybe 0.
It is the value of the discriminant of a quadratic equation.
To find the solution to this equation, you need to rearrange the terms and solve for the variable. 4 = 2b + b^2 can be rewritten as b^2 + 2b - 4 = 0. You can then solve this quadratic equation by factoring, completing the square, or using the quadratic formula.
With a formula, you know the variable's value, and you have to calculate the value of the function of it. With an equation, you know the function's value, and you have to calculate the value of the variable.
With a formula, you know the variable's value, and you have to calculate the value of the function of it. With an equation, you know the function's value, and you have to calculate the value of the variable.
Using the quadratic equation formula the value of x is -8 or 5
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dunctions are not set equal to a value
Using the discriminant formula for a quadratic equation k has a value of 8/25 or maybe 0.
It is the value of the discriminant of a quadratic equation.
x = 9/2 or x = -2 Solved by using the quadratic equation formula.
To find the solution to this equation, you need to rearrange the terms and solve for the variable. 4 = 2b + b^2 can be rewritten as b^2 + 2b - 4 = 0. You can then solve this quadratic equation by factoring, completing the square, or using the quadratic formula.
The quadratic equation is y=ax^2 +bx +c. So, you substitute in the values of a, b, and c to the quadratic formula (x= -b +/- \|b^2-4ac all over 2a) in order to find the x value then, substitute in x to the quadratic equation and solve. You will have point (x,y) to graph
You substitute the value of the variable into the quadratic equation and evaluate the expression.
It too will have a value of 5