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Could there be a quadratic function that has an undefined axis of symmetry?
Yes and this will happen when the discriminant of a quadratic equation is less than zero meaning it has no real roots.
How do you find the line of symmetry in a quadratic equation?
Well,this is an impossible question to answer.The world may never know
What is the equation for the axis of symmetry of the quadratic function f(x) 3x2 12x - 2?
It is x = +/- 2 depending on whether the second term in the equation is -12x or +12x.
What is the line of symmetry for the parabola whose equation is y equals -x2 plus x plus 3?
For a quadratic equation y=Ax2+Bx+C, the line of symmetry is given by x=-B/2ASo for the equation y=-x2+x+3, B is 1 and A is -1, so the line of symmetry isx=1/2
The equation for the axis of symmetry is?
Your equation must be in y=ax^2+bx+c form Then the equation is x= -b/2a That is how you find the axis of symmetry
What is the axis of symmetry of a quadratic equation?
If a quadratic function has the points (-4,0) and (14,0), what is equation of the axis of symmetry?
Could there be a quadratic function that has an undefined axis of symmetry?
Yes and this will happen when the discriminant of a quadratic equation is less than zero meaning it has no real roots.
What is the formula for finding the line of symmetry for a quadratic equation?
the formula is negative b divided by 2 times a
How do you find the line of symmetry in a quadratic equation?
Well,this is an impossible question to answer.The world may never know
What is the equation for the axis of symmetry of the quadratic function f(x) 3x2 12x - 2?
It is x = +/- 2 depending on whether the second term in the equation is -12x or +12x.
What is the line of symmetry for the parabola whose equation is y equals -x2 plus x plus 3?
For a quadratic equation y=Ax2+Bx+C, the line of symmetry is given by x=-B/2ASo for the equation y=-x2+x+3, B is 1 and A is -1, so the line of symmetry isx=1/2
How do you find the gradient of a quadratic equation?
First the formula is g(x)=ax2+bx+c First find where the parabola cuts the x axis Then find the equation of the axis of symmetry Then
How do you find the axis of symmetry for a quadratic equation?
Complete the square, then find the value of x that would make the bracket zero ax^2 + bx + c = 0 line of symmetry is x = (-b/2a)
What is the axis of symmetry for y-x2 2x-4?
To find the axis of symmetry for the quadratic equation ( y = -x^2 + 2x - 4 ), you can use the formula ( x = -\frac{b}{2a} ), where ( a ) and ( b ) are the coefficients from the equation in standard form ( y = ax^2 + bx + c ). Here, ( a = -1 ) and ( b = 2 ). Plugging in the values, the axis of symmetry is ( x = -\frac{2}{2 \times -1} = 1 ). Thus, the axis of symmetry is ( x = 1 ).
How do you find the axis of symmetry of the quadratic function.?
The axis of symmetry of a quadratic function in the form (y = ax^2 + bx + c) can be found using the formula (x = -\frac{b}{2a}). This vertical line divides the parabola into two mirror-image halves. To find the corresponding (y)-coordinate, substitute the axis of symmetry value back into the quadratic function.
Y equals ax2 - 2x - 3 The line of symmetry is x equals 1 Does an equal 1 or -1 or 2?
For the equation ax2-2x-3, the quadratic coefficients are:a=a,b=-2c=-3.The equation of the line of symmetry is:x= -b/2aAs we know that the line of symmetry is x=1,we get:1 = 2/2a, so2a = 2and a = 1.We get a bowl-shaped parabola, whose lowest point is (1,-4).
The equation for the axis of symmetry is?
Your equation must be in y=ax^2+bx+c form Then the equation is x= -b/2a That is how you find the axis of symmetry
