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The point (2 -5) and has a slope of -7. What is the equation for this line in point-slope form?
The point-slope form of a linear equation is given by the formula ( y - y_1 = m(x - x_1) ), where ( m ) is the slope and ( (x_1, y_1) ) is a point on the line. For the point (2, -5) with a slope of -7, the equation becomes ( y - (-5) = -7(x - 2) ). Simplifying this, we get ( y + 5 = -7(x - 2) ). Therefore, the equation in point-slope form is ( y + 5 = -7(x - 2) ).
Which equation in point-slope form contains the point (4 1) and has slope 3?
To write the equation in point-slope form, use the formula (y - y_1 = m(x - x_1)), where ((x_1, y_1)) is the point and (m) is the slope. Substituting the point (4, 1) and the slope 3 into the formula gives us (y - 1 = 3(x - 4)). This is the point-slope form of the equation.
What is the formula for finding mid point?
[(X1+X2)/2],[(y1+y2)/2]
What is The length of a perpendicular segment from the point to the line?
The length of a perpendicular segment from a point to a line is the shortest distance between that point and the line. This length can be calculated using the formula given the coordinates of the point and the line's equation. Specifically, if the line is represented in the form Ax + By + C = 0, and the point's coordinates are (x₀, y₀), the length can be found using the formula: ( \text{Distance} = \frac{|Ax₀ + By₀ + C|}{\sqrt{A^2 + B^2}} ). This distance is always positive and represents the minimum separation between the point and the line.
What formula can he use to determine the distance from point C to point D?
To determine the distance from point C to point D, he can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ), where ( (x_1, y_1) ) are the coordinates of point C and ( (x_2, y_2) ) are the coordinates of point D. By plugging in the respective coordinates into this formula, he can calculate the straight-line distance between the two points.
What is midpoint formula?
The mid point formula is m= X1+X2/2 y1+y2/2
What is the formula for point slope form?
Y-y1=m(x-x1)
What is the formula of point slope form?
y-y1=m(x-x1) this is the answer
Which equation in point-slope form contains the point (4 1) and has slope 3?
To write the equation in point-slope form, use the formula (y - y_1 = m(x - x_1)), where ((x_1, y_1)) is the point and (m) is the slope. Substituting the point (4, 1) and the slope 3 into the formula gives us (y - 1 = 3(x - 4)). This is the point-slope form of the equation.
What is the formula for finding mid point?
[(X1+X2)/2],[(y1+y2)/2]
Is point slope form the same as equation of a line?
yes the formula is y=mx+b
What is The length of a perpendicular segment from the point to the line?
The length of a perpendicular segment from a point to a line is the shortest distance between that point and the line. This length can be calculated using the formula given the coordinates of the point and the line's equation. Specifically, if the line is represented in the form Ax + By + C = 0, and the point's coordinates are (x₀, y₀), the length can be found using the formula: ( \text{Distance} = \frac{|Ax₀ + By₀ + C|}{\sqrt{A^2 + B^2}} ). This distance is always positive and represents the minimum separation between the point and the line.
What formula can he use to determine the distance from point C to point D?
To determine the distance from point C to point D, he can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ), where ( (x_1, y_1) ) are the coordinates of point C and ( (x_2, y_2) ) are the coordinates of point D. By plugging in the respective coordinates into this formula, he can calculate the straight-line distance between the two points.
How do you write point 2 cents in decimal form?
$0.02 is 2 cents in decimal form. No. 2 cents is 2 cents. "Point 2 cents" would be 0.2 of a Cent. Therefore: $0.002
What is International Gravity Formula?
how is the formula of (1+0.005279sin^2+0.000023sin^4) come from and what is a complete form of this formula?please answere
What is the equation line in point slope passing through (-2-2) and (-5-3)?
To find the equation of the line in point-slope form that passes through the points (-2, -2) and (-5, -3), we first need to calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the points, we get ( m = \frac{-3 - (-2)}{-5 - (-2)} = \frac{-1}{-3} = \frac{1}{3} ). Using point-slope form ( y - y_1 = m(x - x_1) ) with point (-2, -2), the equation becomes ( y + 2 = \frac{1}{3}(x + 2) ).
Write in point slope form a lone parallel to y 1 2 plus 3 and through -1 4?
To write the equation of a line in point-slope form that is parallel to ( y = \frac{1}{2}x + 3 ), we first note that the slope of the given line is (\frac{1}{2}). Using the point ((-1, 4)) and the slope (\frac{1}{2}), we apply the point-slope formula (y - y_1 = m(x - x_1)). This gives us the equation: [ y - 4 = \frac{1}{2}(x + 1) ]
