To find the equation in point-slope form for the line that passes through the points (3, 5) and (2, 3), we first calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the points gives us ( m = \frac{3 - 5}{2 - 3} = \frac{-2}{-1} = 2 ). Using point-slope form ( y - y_1 = m(x - x_1) ) with point (3, 5), the equation becomes ( y - 5 = 2(x - 3) ).
The equation for the given points is y = x+4 in slope intercept form
If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6
It is y = 2.
Answer this question…y = 2x + 6
A line that is parallel to the y-axis is a vertical line. The equation of a vertical line is of the form ( x = k ), where ( k ) is a constant. Since the line passes through the points ( (4, y) ) and ( (3, y) ), the line that is parallel to the y-axis and passes through these points would have the equation ( x = 4 ) or ( x = 3 ), depending on which point you choose.
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
The equation for the given points is y = x+4 in slope intercept form
If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6
It is y = 2.
Y= -3x + 8
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
Points: (0. 5) and (2, 3) Slope: -1 Equation: y = -x+5
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
Answer this question…y = 2x + 6
A line that is parallel to the y-axis is a vertical line. The equation of a vertical line is of the form ( x = k ), where ( k ) is a constant. Since the line passes through the points ( (4, y) ) and ( (3, y) ), the line that is parallel to the y-axis and passes through these points would have the equation ( x = 4 ) or ( x = 3 ), depending on which point you choose.
If the points are (1,5) and (0,0) y = 5x