The area of a Reuleaux triangle with constant width s is
0.5*[pi - sqrt(3)]*s2
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For a Reuleaux triangle: Area = 1/2(π - √3)diameter2 = 1/2(π - √3)112 ≈ 85.28m2
Area = 1/2*{pi - sqrt(3)}*r^2 = 11.28 square units, approx.
its 1/2 the area of a circle with the length of on side of the triangle as the radius. then subtract 2 times the area of said equilateral triangle. (to find its height, use the Pythagorean theory. split the triangle in half to get its height, the base will be 1/2 the length of its side. Type your answer here...
Reuleaux triangle
Area of a triangle: 0.5*base*perpendicular height