The median is a "midpoint" - for a set of numbers, it is the value for which half are above and half are below. Averages can be thrown off by extreme values, but medians are less susceptible. To calculate it, take your set of numbers, and arrange them from smallest to largest or vice versa. If you have an odd number of values, your median is just the one in the middle; if you have an even number, it's the mean of the two in the middle. So, the median of 1, 3, and 6 is 3, and the median of 1, 100, 101, and 102 is the mean of 100 and 101, or 100.5 . If you have values x1, x2, ..., and xn (n is a positive integer) where they are arranged in numerical order (either xi <= x(i+1) for i = 1, 2, ..., n-1 -or- xi >= x(i+1) for i = 1, 2, ..., n-1), a simple formula to calculate the median is to first determine if n is even or odd. If odd, just return the "middle" value - i.e., xj where j is n/2 rounded up to the next integer. If n is even, simply take the mean of xk and x(k+1) where k = n divided by 2.
Simple answer:Divide the total number of observations (plus 1, if small) by 2 to find the middle rank.Look at the cumulative frequencies for the grouped data and find the group in which the middle rank would appear. That is the median group.More sophisticated answer:Withing the median group, interpolate.
D=E1+((dN/10)-Cf)(I)/F The formula of deciles is different for grouped and ungrouped data.
You put the numbers in order from least to greatest then, start at the beginning and end, and cross out one... two... three... four..., then so on, until you have only one number in the middle. Example 27,44,45,46,52; cross out 27, then... 52, then... 44, then... 46, then... 45 is the last answer left, so 45, is your answer. man, whoever answered this question is a total fool. they wanted to know how to find the median of GROUPED DATA not just the median. wow what a fool.
On the cumulative frequecy diagram, find 50% on the frequency [usually, vertical] axis. Draw a line to the graph and then drop a perpendicular to the other [horizontal] axis. Where it hits the second axis is the median value.
In continuous grouped data the data is collected continuously and in groups. Data collected is in class intervals the actual data values are not visible.
Simple answer:Divide the total number of observations (plus 1, if small) by 2 to find the middle rank.Look at the cumulative frequencies for the grouped data and find the group in which the middle rank would appear. That is the median group.More sophisticated answer:Withing the median group, interpolate.
A frequency diagram or, for grouped data, an histogram.
Mean = a + [
You will need to put the un-grouped data in ascending or descending order. If you have an odd number of data values the formula for the median value is (n+1)/2. Example my data in ascending order is 0, 2, 4, 5, 7, 8, 9. I have 7 data values. The median is the value (7+1)/2 = 4th value from left or right which is 5. For an even number of data values, you will need to calculate the median and it may not be a data value. It will be the mean of the two center values. Use the formula n/2 to get the left most value. Example my data in ascending order is 0, 2, 4, 5, 7, 8. I have 6 data values. The left most value I will use to calculate the median is 6/2 = 3rd. The 3rd value from the left is 4. The next value is 5. Median is (4+5)/2 = 4.5.
it is used to find mean<median and mode of grouped data
Mean, median and mode are ways to find averages. The mode is the most common answer in a set of data. The median the number that is in the middle when the numbers are put in order. The mean is the statical average.
ungruped data are those type of data which are not proper arranged or order
Mean and median are the measures of central location that always have one value. This is true for a set of grouped or ungrouped data.
Not sure what a "grouped of data" means!
D=E1+((dN/10)-Cf)(I)/F The formula of deciles is different for grouped and ungrouped data.
L + d1/d1+d2 x w
You put the numbers in order from least to greatest then, start at the beginning and end, and cross out one... two... three... four..., then so on, until you have only one number in the middle. Example 27,44,45,46,52; cross out 27, then... 52, then... 44, then... 46, then... 45 is the last answer left, so 45, is your answer. man, whoever answered this question is a total fool. they wanted to know how to find the median of GROUPED DATA not just the median. wow what a fool.