84, if you fit the quadratic rule Un= 32n2- 144n + 148 for n = 1, 2, 3, ...
Or
-1.33... if you fit the power rule Un= -108/(-3)nfor n = 1, 2, 3, ...
There are infinitely more options. Give me any fourth number and I will find you a term to value rule that will work for that value.
36
If the first term is 12 and the seventh term is 36, then we have gone up 36-12 in the space of 6 term changes. This is 24 per 6 changes, which can be written as the division 24/6. This works out as 4. Thus the common difference in the sequence is 4.
12
The given sequence is 12, 20, 28, 36, 44. To find the nth term, observe that the difference between consecutive terms is consistently 8. Therefore, we can express the nth term as ( a_n = 12 + 8(n - 1) ), which simplifies to ( a_n = 8n + 4 ). Thus, the nth term of the sequence is ( a_n = 8n + 4 ).
The lowest term of 36 and 3 is: 3 as 36 goes into 3, 12 times and 3 goes into three once.
36
If the first term is 12 and the seventh term is 36, then we have gone up 36-12 in the space of 6 term changes. This is 24 per 6 changes, which can be written as the division 24/6. This works out as 4. Thus the common difference in the sequence is 4.
12
9, 12,16,21,27,34,42 42 is the 7th term 9+3=12 12+4=16 16+5=21 21+6=27 27+7=34 34+8=42, the 7th term
The nth term is (36 - 4n)
96
12
1/4=9/36 3/9=12/36 9+12=21/36
12The next number in the sequence is the previous # divided by 3. So, 324/3 = 108; 108/3 = 36; 36/3 = 12
The lowest term of 36 and 3 is: 3 as 36 goes into 3, 12 times and 3 goes into three once.
36
36