y = ax2 + bx + c
It is a quadratic function which represents a parabola.
f(x) = ax^2 + bx + c, where a != 0 (for obvious reason: it wouldn't be a quadratic function)
It can be written in the form y = ax2 + bx + c where a, b and c are constants and a ≠0
I have a code for 16 bit subtraction.. just replace ax by al,bx by bl etc... .code main proc mov ax,@data mov ds,ax lea dx,msg ;printing msg mov ah,09h int 21h mov ax,x ;ax=x(any number) mov bx,y ;bx=y( " ") cmp ax,0 ;jump to l3 if ax is negtive jb l3 cmp bx,0 ;jump to l6 if bx is negative jb l6 cmp ax,bx ;if ax<bx,then jump to l1 jl l1 sub ax,bx ;else normal sub mov diff,ax ;diff=result is stored jmp l2 l1: ;iff (+)ax<(+)bx neg bx ;bx=-bx clc add ax,bx neg ax ;-ans=ans mov diff,ax mov dx,2dh ;print '-' mov ah,02h int 21h jmp l2 l3: ;iff (-)ax neg ax ;-ax=ax cmp bx,0 ;jump to l4 if bx is negative jb l4 clc add ax,bx ;ax=(+)ax+(+)bx mov ax,diff mov dx,2dh ;print '-' mov ah,02h int 21h jmp l2 l4: ;if (-)ax & (-)bx neg bx ;-bx=bx cmp ax,bx ;if ax>bx then jump to l5 jg l5 sub ax,bx ;else ax-bx mov diff,ax mov dx,2dh ;print '-' mov ah,02h int 21h jmp l3 l5: ;if(-)ax>(-)bx xchg ax,bx ;exchange ax and bx sub ax,bx ;ax-bx mov diff,ax ;ans is positive jmp l2 l6: ;iff (-)bx neg bx ;-bx=bx add ax,bx ;ax-(-)bx mov diff,ax ;ans will be positive mov ah,4ch int 21h main endp
ax^2+bx+c=0 is the standard form of a quadratic function.
f(x) = bX is not an exponential function so the question makes no sense.
y = x2 is the parent function, but it can be in the form y = ax2 + bx + c
ax2 +bx + c = 0
y = ax2 + bx + c
It is a quadratic function which represents a parabola.
A second-degree polynomial function is a function of the form: P(x) = ax2 + bx + cWhere a ≠ 0.
(0,a)
f(x) = ax^2 + bx + c, where a != 0 (for obvious reason: it wouldn't be a quadratic function)
It can be written in the form y = ax2 + bx + c where a, b and c are constants and a ≠0
If the quadratic function is written as ax2 + bx + c, then it has no x-intercepts if the discriminant, (b2 - 4ac), is negative.
in general, the y-intercept of the function f(X)= axb^x is the point__.