It's a telephone switchboard
y = ax2 + bx + c
It is a quadratic function which represents a parabola.
f(x) = ax^2 + bx + c, where a != 0 (for obvious reason: it wouldn't be a quadratic function)
It can be written in the form y = ax2 + bx + c where a, b and c are constants and a ≠0
To find the inverse of the function ( F(X) = BX ), where ( B ) is a constant, you need to solve for ( X ) in terms of ( F(X) ). This gives you ( X = \frac{F(X)}{B} ). Thus, the inverse function is ( F^{-1}(Y) = \frac{Y}{B} ), where ( Y ) is the output of the original function.
ax^2+bx+c=0 is the standard form of a quadratic function.
f(x) = bX is not an exponential function so the question makes no sense.
y = x2 is the parent function, but it can be in the form y = ax2 + bx + c
ax2 +bx + c = 0
y = ax2 + bx + c
It is a quadratic function which represents a parabola.
A second-degree polynomial function is a function of the form: P(x) = ax2 + bx + cWhere a ≠ 0.
(0,a)
The BX wire function refers to the use of BX (or armored) cable in electrical installations. BX cable is characterized by its flexible metal conduit that provides both protection and grounding for the insulated conductors inside. This type of wiring is often used in residential and commercial applications due to its durability and resistance to physical damage. It is particularly beneficial in environments where exposure to moisture or mechanical stress is a concern.
f(x) = ax^2 + bx + c, where a != 0 (for obvious reason: it wouldn't be a quadratic function)
It can be written in the form y = ax2 + bx + c where a, b and c are constants and a ≠0
To find the inverse of the function ( F(X) = BX ), where ( B ) is a constant, you need to solve for ( X ) in terms of ( F(X) ). This gives you ( X = \frac{F(X)}{B} ). Thus, the inverse function is ( F^{-1}(Y) = \frac{Y}{B} ), where ( Y ) is the output of the original function.