It's a telephone switchboard
y = ax2 + bx + c
It is a quadratic function which represents a parabola.
f(x) = ax^2 + bx + c, where a != 0 (for obvious reason: it wouldn't be a quadratic function)
It can be written in the form y = ax2 + bx + c where a, b and c are constants and a ≠0
A cubic function can be expressed in the form ( f(x) = ax^3 + bx^2 + cx + d ). To reflect this function over the x-axis, you negate it, resulting in ( f(x) = -ax^3 - bx^2 - cx - d ). To apply a vertical shift down by 2, you subtract 2 from the entire function, leading to the final equation: ( f(x) = -ax^3 - bx^2 - cx - (d + 2) ).
ax^2+bx+c=0 is the standard form of a quadratic function.
f(x) = bX is not an exponential function so the question makes no sense.
y = x2 is the parent function, but it can be in the form y = ax2 + bx + c
ax2 +bx + c = 0
y = ax2 + bx + c
It is a quadratic function which represents a parabola.
A second-degree polynomial function is a function of the form: P(x) = ax2 + bx + cWhere a ≠ 0.
(0,a)
f(x) = ax^2 + bx + c, where a != 0 (for obvious reason: it wouldn't be a quadratic function)
It can be written in the form y = ax2 + bx + c where a, b and c are constants and a ≠0
The form of the quadratic is ax2+bx+c, so the discriminant is b2-4ac.
ax2 + bx + c = 0 where a, b and c are constants and a is not 0.