The gradient of a linear equation is also known as slope. Slope is the (Change in Y)/(Change in X). Luckily there is a simple way to find out the slope in a simple linear equation. A simple linear equation can be written as: y = mx + b where m = slope (gradient) and b = y-intercept I assume your equation is x = 2y + 1. This may look like it fits the equation above but it does not. The equation needs to be solved for y. x = 2y + 1 (Subtract 1 from both sides) x - 1 = 2y (Divide both sides by 2) x/2 - 1/2 = y Now the equation is in the proper form. y = 1/2x - 1/2 Looking at the first equation: m = slope = 1/2. The slope (or gradient) is 1/2
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Definition of the inverse of a function.Let f and g be two functions such thatf(g(x)) = x for every x in the domain of g andg(f(x)) = x for every x in the domain of f.The function g is the inverse of the function f, and the domain of f is equal to the range of g, and vice versa.Example: Find the inverse of y1 = 2x + 7Solutiony1 = 2x + 7 interchange x and y;x = 2y1 + 7 solve for y;x - 7 = 2y1 + 7 -7 subtract 7 to both sides;x - 7 = 2y1 divide by 2 both sides;(x - 7)/2 = y1 replace y1 with y2;y2 = (x - 7)/2Thus, the inverse of y1 = 2x +7 is y2 = (x -7)/2Let's check if this is true according to the above definition:Let y1 = f(x) = 2x +7 and y2 = g(x) = (x -7)/21. f(g(x))= x ?f(x) = 2x + 7f((x - 7)/2) = 2[(x -7)/2] + 7 = x - 7 + 7 = x True2. g(f(x) = x ?g(x) = (x - 7)/2g(2x + 7) = [(2x + 7) - 7]/2 = 2x/2 = x True
y = x - 4/x so gradient = dy/dx = 1 + 4/x2 When y = 3, x - 4/x = 3 x2 - 3x - 4 = 0 so x = -1 or x = 4 When x = -1, gradient = 1 + 4/(-1)2 = 1 + 4/1 = 1+4 = 5 When x = 4, gradient = 1 + 4/(4)2 = 1 + 4/16 = 1+1/4 = 1.25
When equation of line is y=-4x+3, Gradient is -4 (as seen from the coefficient of x) and the y-intercept is +3 (point where x=0)
Theoretically, yes. For lines parallel to y-axis, gradient is zero. Eg, x=4.
x+y=2 the gradient is -1
Gradient to the curve at any point is the derivative of y = x2 So the gradient is d/dx of x2 = 2x. When x = 2, 2x = 4 so the gradient of the tangent at x = 2 is 4.
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Definition of the inverse of a function.Let f and g be two functions such thatf(g(x)) = x for every x in the domain of g andg(f(x)) = x for every x in the domain of f.The function g is the inverse of the function f, and the domain of f is equal to the range of g, and vice versa.Example: Find the inverse of y1 = 2x + 7Solutiony1 = 2x + 7 interchange x and y;x = 2y1 + 7 solve for y;x - 7 = 2y1 + 7 -7 subtract 7 to both sides;x - 7 = 2y1 divide by 2 both sides;(x - 7)/2 = y1 replace y1 with y2;y2 = (x - 7)/2Thus, the inverse of y1 = 2x +7 is y2 = (x -7)/2Let's check if this is true according to the above definition:Let y1 = f(x) = 2x +7 and y2 = g(x) = (x -7)/21. f(g(x))= x ?f(x) = 2x + 7f((x - 7)/2) = 2[(x -7)/2] + 7 = x - 7 + 7 = x True2. g(f(x) = x ?g(x) = (x - 7)/2g(2x + 7) = [(2x + 7) - 7]/2 = 2x/2 = x True
Y divided by X axix- Y/X
Differentiate the curve twice and then enter a value for x. If the answer is positive, the gradient is increasing at that point. If the answer is negative, the gradient is decreasing at that point. And if the answer is zero, the gradient is not changing.
y = x - 4/x so gradient = dy/dx = 1 + 4/x2 When y = 3, x - 4/x = 3 x2 - 3x - 4 = 0 so x = -1 or x = 4 When x = -1, gradient = 1 + 4/(-1)2 = 1 + 4/1 = 1+4 = 5 When x = 4, gradient = 1 + 4/(4)2 = 1 + 4/16 = 1+1/4 = 1.25
When equation of line is y=-4x+3, Gradient is -4 (as seen from the coefficient of x) and the y-intercept is +3 (point where x=0)
Theoretically, yes. For lines parallel to y-axis, gradient is zero. Eg, x=4.
A positive gradient is a characteristic of a function whose value increases as the value of the argument increases. So, if y is a function, f(x), of x, then an increase in the value of x is accompanied by an increase in the value of y.
The gradient of the function y = 3x + 5 is simply the coefficient of x, which is 3. In this context, the gradient represents the slope of the line that the function represents. This means that for every unit increase in x, y will increase by 3 units.
The approximate gradient of the hill between points x and y can be calculated by taking the difference in elevation between the two points and dividing it by the horizontal distance between them. This is often expressed as the rise over run. If the elevation at point x is higher than at point y, the gradient will be negative, indicating a downhill slope, while a positive gradient indicates an uphill slope. The steeper the hill, the larger the absolute value of the gradient.