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Which line is perpendicular to 2x-8y plus 23 equals 0?
4x + y + c = 0 or, for a line going through a given point (xo, yo): y + 4x - (xo + yo) = 0 The gradient of a line multiplied by the gradient of a line perpendicular to it is -1; or in other words: The gradient of the perpendicular line is the negative reciprocal of the gradient of the line. Thus: 2x - 8y + 23 = 0 ⇒ 8y = 2x + 23 ⇒ y = 1/4x + 23/8 ⇒ gradient of perpendicular line is -1 ÷ 1/4 = -4 Thus the equation of the perpendicular line to 2x - 8y + 23 = 0 is 4x + y + c = 0. To find the line through point (xo, yo) perpendicular to 2x - 8y + 23 = 0, use the format: y - yo = m(x - xo) ⇒ y - yo = -4(x - xo) ⇒ y + 4x - (xo + yo) = 0
What is the equation of a line with gradient -3 that goes through the origin?
The equation of a line can be expressed in the slope-intercept form, which is ( y = mx + b ), where ( m ) is the gradient and ( b ) is the y-intercept. Given a gradient of -3 and that the line passes through the origin (0,0), the y-intercept ( b ) is 0. Thus, the equation of the line is ( y = -3x ).
The gradient of the line is y equals -4 x plus 3 is?
When equation of line is y=-4x+3, Gradient is -4 (as seen from the coefficient of x) and the y-intercept is +3 (point where x=0)
How do you name the equation of a line that is perpendicular to y equals 1 half x-3 and goes through the point x equals 0 and y equals 3?
L1: y = 1/2*x - 3Gradient of the line = 1/2Negative reciprocal of gradient = -1/(1/2) = -2That is, gradient of perpendicular = -2.This line goes through (0,3),(y - 3) = 2*(x - 0)y - 3 = 2xy = 2x + 3L1: y = 1/2*x - 3Gradient of the line = 1/2Negative reciprocal of gradient = -1/(1/2) = -2That is, gradient of perpendicular = -2.This line goes through (0,3),(y - 3) = 2*(x - 0)y - 3 = 2xy = 2x + 3L1: y = 1/2*x - 3Gradient of the line = 1/2Negative reciprocal of gradient = -1/(1/2) = -2That is, gradient of perpendicular = -2.This line goes through (0,3),(y - 3) = 2*(x - 0)y - 3 = 2xy = 2x + 3L1: y = 1/2*x - 3Gradient of the line = 1/2Negative reciprocal of gradient = -1/(1/2) = -2That is, gradient of perpendicular = -2.This line goes through (0,3),(y - 3) = 2*(x - 0)y - 3 = 2xy = 2x + 3
What is approximate gradient?
The gradient of a line is the same as the slope of a line. It will tell someone measuring the line how straight the line is.
How do you work out the gradient of a perpendicular line?
basically the reciprocal of the original lines gradient is going to be the gradient for the perpendicular line (remember the signs should switch). For example if i had a line with the gradient of 3, then the gradient of the perpendicular line will be -1over3. But if the line had the gradient of -3, then the line perpendicular to that line will have the gradient 1over3.
Which line is perpendicular to 2x-8y plus 23 equals 0?
4x + y + c = 0 or, for a line going through a given point (xo, yo): y + 4x - (xo + yo) = 0 The gradient of a line multiplied by the gradient of a line perpendicular to it is -1; or in other words: The gradient of the perpendicular line is the negative reciprocal of the gradient of the line. Thus: 2x - 8y + 23 = 0 ⇒ 8y = 2x + 23 ⇒ y = 1/4x + 23/8 ⇒ gradient of perpendicular line is -1 ÷ 1/4 = -4 Thus the equation of the perpendicular line to 2x - 8y + 23 = 0 is 4x + y + c = 0. To find the line through point (xo, yo) perpendicular to 2x - 8y + 23 = 0, use the format: y - yo = m(x - xo) ⇒ y - yo = -4(x - xo) ⇒ y + 4x - (xo + yo) = 0
Why are all horizontal lines parallel?
By definition, lines are parallel if they have the same gradient (slope). Any horizontal line has a gradient of 0, so it is parallel to any other horizontal line.
What is approximate gradient?
The gradient of a line is the same as the slope of a line. It will tell someone measuring the line how straight the line is.
How does a gradient affect the steepness of the line?
The higher the gradient, the more steeper the line will be.
What is the equation of a line with gradient -3 that goes through the origin?
The equation of a line can be expressed in the slope-intercept form, which is ( y = mx + b ), where ( m ) is the gradient and ( b ) is the y-intercept. Given a gradient of -3 and that the line passes through the origin (0,0), the y-intercept ( b ) is 0. Thus, the equation of the line is ( y = -3x ).
The gradient of the line is y equals -4 x plus 3 is?
When equation of line is y=-4x+3, Gradient is -4 (as seen from the coefficient of x) and the y-intercept is +3 (point where x=0)
How do you name the equation of a line that is perpendicular to y equals 1 half x-3 and goes through the point x equals 0 and y equals 3?
L1: y = 1/2*x - 3Gradient of the line = 1/2Negative reciprocal of gradient = -1/(1/2) = -2That is, gradient of perpendicular = -2.This line goes through (0,3),(y - 3) = 2*(x - 0)y - 3 = 2xy = 2x + 3L1: y = 1/2*x - 3Gradient of the line = 1/2Negative reciprocal of gradient = -1/(1/2) = -2That is, gradient of perpendicular = -2.This line goes through (0,3),(y - 3) = 2*(x - 0)y - 3 = 2xy = 2x + 3L1: y = 1/2*x - 3Gradient of the line = 1/2Negative reciprocal of gradient = -1/(1/2) = -2That is, gradient of perpendicular = -2.This line goes through (0,3),(y - 3) = 2*(x - 0)y - 3 = 2xy = 2x + 3L1: y = 1/2*x - 3Gradient of the line = 1/2Negative reciprocal of gradient = -1/(1/2) = -2That is, gradient of perpendicular = -2.This line goes through (0,3),(y - 3) = 2*(x - 0)y - 3 = 2xy = 2x + 3
What is the gradient of the straight line and their angles of inclination a-2 0 and B 6 -4?
Gradient = [-4 - 0]/[6 - (-2)] = 4/8 = 0.5 Angle of inclination = arctan(0.5) = 0.464 radians.
Can you have 0 run in a rise over run problem?
Yes, but the the line is vertical and the slope (or gradient) is undefined.
What is the gradient of (13) (43)?
If you mean points of (1, 3) and (4, 3) then the gradient is 0 and it is a horizontal straight line parallel to the x axis on the Cartesian plane.
What is the gradient of a vertical line?
The gradient of a straight line cannot be defined- it's infinity.
