Draw a x and y axis coordinate
Plot -10 on the y axis. From that point go down 1 and to the right one
Make a new dot there.
Join the two dots
Continue the line past the dots in a straight line.
Put arrows on both ends of the line
ta da the graph of -x -10
The graph of ( y = (x + 4)^{10} - 2 ) undergoes two transformations from the basic graph of ( y = x^{10} ). First, it shifts 4 units to the left due to the ( (x + 4) ) term. Then, it shifts down 2 units because of the subtraction of 2.
To graph the equation ( y = 10 ), draw a horizontal line across the y-axis at the point where ( y ) equals 10. This line will extend infinitely in both directions along the x-axis, as the value of ( y ) remains constant at 10 regardless of ( x ). Each point on this line will have the coordinates ( (x, 10) ) for any value of ( x ).
It seems there is a typo in your function rule. If you meant ( f(x) = 10 + 4x ), then the points on the graph can be determined by substituting different x-values. For example, if ( x = 0 ), then ( f(0) = 10 ) (point (0, 10)). If ( x = 1 ), then ( f(1) = 14 ) (point (1, 14)). Other points can be calculated similarly.
graph x+4<5
If you mean: 2x-y = 10 then the x intercept is (5, 0) and the y intercept is (0, -10)
x is the horizontal axis on a graph. It can also represent multiplication or the word "by", for example a room is called 10' x 10' (10 by 10).
x is the horizontal axis on a graph. It can also represent multiplication or the word "by", for example a room is called 10' x 10' (10 by 10).
5x - 10 = 20Add 10 to each side:5x = 30Divide each side by 5:x = 6If you feel that you must graph this equation for some reason,then your graph is a vertical line, parallel to the y-axis, passingthrough the point [ x=6 ] on the x-axis.
I am assuming the you are talking about the graph of the derivative. The graph of the derivative of F(x) is the graph such that, for any x, the value of x on the graph of the derivative of F(x) is the slope at point x in F(x).
To translate the graph y = x to the graph of y = x - 6, shift the graph of y = x down 6 units.
If: 6x2+11x-10 = 0 Then: x = -5/2 and x = 2/3
To graph the equation ( y = 10 ), draw a horizontal line across the y-axis at the point where ( y ) equals 10. This line will extend infinitely in both directions along the x-axis, as the value of ( y ) remains constant at 10 regardless of ( x ). Each point on this line will have the coordinates ( (x, 10) ) for any value of ( x ).
It seems there is a typo in your function rule. If you meant ( f(x) = 10 + 4x ), then the points on the graph can be determined by substituting different x-values. For example, if ( x = 0 ), then ( f(0) = 10 ) (point (0, 10)). If ( x = 1 ), then ( f(1) = 14 ) (point (1, 14)). Other points can be calculated similarly.
If you mean: y = 6x^2+11x-10 then x = 2/3 and x = -5/2
graph x+4<5
If you mean: 2x-y = 10 then the x intercept is (5, 0) and the y intercept is (0, -10)
If you mean: 2x-y = 10 then the x intercept is (5, 0) and the y intercept is (0, -10)