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If you mean: y = 6x^2+11x-10 then x = 2/3 and x = -5/2

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Q: Where does the graph of y 6x2 11x 10 cross the x-axis?
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Related questions

Where does the graph of y 6x2 11x minus 10 cross the x axis?

If: 6x2+11x-10 = 0 Then: x = -5/2 and x = 2/3


How do you factor 6x2-11x?

x(6x - 11)


Factor the polynomial expression 6x2 plus 11x plus 3?

6x2 + 11x + 3 = 6x2 + 9x + 2x + 3 = 3x(2x + 3) + 1(2x + 3) = (2x + 3)(3x + 1)


Are (3x 1) and (2x 3) the binomial factors of 6x2 11x 3?

If you mean: (3x+1) and (2x+3) are factors of 6xsquared+11x+3 then yes they are


If they distance traveled is 5x3-6x2 plus 3x plus 14 mi and the rate is x plus 1 mph What is an expression for the time traveled?

Distance travelled = 5x3 - 6x2 + 3x + 14 = 5x3 + 5x2 - 11x2 - 11x + 14x + 14 = 5x2(x + 1) - 11x(x + 1) + 14(x + 1) = (x + 1)(5x2 - 11x + 14) Then time = distance/rate = (x + 1)(5x2 - 11x + 14) / (x+1) = 5x2 - 11x + 14


Factor 6x2-11x plus 5?

Assuming that the first operator is 6x^2. The factors are (6x-5)*(x-1)


Factor 6x2 plus 11x-10?

6x2 + 11x - 10 = (6x2 + 15x) - (4x + 10) = 3x(2x + 5) - 2(2x + 5) = (3x - 2)(2x + 5). Note, first, that the three co-efficients of the original quadratic expression are 6, 11, and -10. We need two numbers whose sum is 11 and whose product is (6)(-10) = -60. These two numbers turn out to be 15 and -4. Thus, we replace the middle term, 11x with 15x - 4x and proceed with the factorisation in the usual way.


Negative three open bracket two x plus oneclose bracket open bracket four plus three x close bracke?

-3(2x + 1)(4 + 3x) = -3[8x + 6x2 + 4 + 3x] = -3[6x2 + 11x + 4] = -18x2 - 33x - 12.


What is the answer to 6x squared minus 5x minus 11?

There can be no answer since there is no equation: only an expression. It is possible to factorise the expression as follows: 6x2 - 5x - 11 = 6x2 + 6x - 11x - 11 = 6x(x + 1) - 11(x + 1) = (x + 1)(6x - 11) Just to add, if you meant 6x2 - 5x - 11 = 0, then the above factorise would give you either (x+1) = 0, or (6x-11)=0, so x=-1 or 11/6


What is the answer to 9 plus 6x2?

9+6x2=21


Area is 36x4-64x2 width is 6x2-8x what is the length in terms of x?

Area 36x4-64x2 and width is 6x2-8x Area = Length * width36x4 -64x2 = L * 6x2 -8x(36x4 -64x2) / (6x2 -8x) = L(36x4 -64x2) / (6x2 -8x) = L((6x2 -8x)2 + 96x3)/ (6x2 -8x) = L1 + 96x3/ (6x2 -8x) = L1 + 96x3/ x(6x -8) = L1 + 96x2/ (6x -8) = L


What is the answer to 6x2-9x-6?

6x2-9x-6 is equal to 66.