90.25 ft2
That depends on the dimensions !... A 1 x 18 rectangle has a perimeter of 38 ! A 2 x 9 rectangle has a perimeter of 22 ! A 3 x 6 rectangle has a perimeter of 18 !
The dimensions are 4 units by 15 units
I suspect the area or the perimeter is missing from this question. There is an infinity of rectangles with a width of 38cm.
To find the minimum perimeter of a rectangle with an area of 84 square units, we need to consider the dimensions of the rectangle. The perimeter ( P ) is given by ( P = 2(l + w) ), where ( l ) is the length and ( w ) is the width. The area constraint ( lw = 84 ) can be optimized by setting ( l ) and ( w ) equal, which occurs at a square. The dimensions for a rectangle with area 84 that minimizes the perimeter are ( l = 12 ) and ( w = 7 ), resulting in a minimum perimeter of ( P = 2(12 + 7) = 38 ) units.
Perimeter = 7+7+12+12 = 38 m
That depends on the dimensions !... A 1 x 18 rectangle has a perimeter of 38 ! A 2 x 9 rectangle has a perimeter of 22 ! A 3 x 6 rectangle has a perimeter of 18 !
90.25 square degers
The perimeter is 38.
the old perimeter is 17 * 2 The old perimeter = 38
An 11 x 8 rectangle will have a perimeter of 38. Add all 4 sides together to get the perimeter,
The dimensions are 4 units by 15 units
I suspect the area or the perimeter is missing from this question. There is an infinity of rectangles with a width of 38cm.
To find the minimum perimeter of a rectangle with an area of 84 square units, we need to consider the dimensions of the rectangle. The perimeter ( P ) is given by ( P = 2(l + w) ), where ( l ) is the length and ( w ) is the width. The area constraint ( lw = 84 ) can be optimized by setting ( l ) and ( w ) equal, which occurs at a square. The dimensions for a rectangle with area 84 that minimizes the perimeter are ( l = 12 ) and ( w = 7 ), resulting in a minimum perimeter of ( P = 2(12 + 7) = 38 ) units.
Perimeter = 7+7+12+12 = 38 m
Perimeter = 11+11+8+8 = 38 inches
(38/4) sqrd
The width is 8 feet