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The GCF of 15ab and 5b squared is 5b.

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Q: What is the greatest common factor of 15ab and 5b2?
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What is the GCF of 15ab and 5b to the second power?

The greatest common factor (GCF) of 15ab and 5b2 is 5b.


What is the greatest common factor of 15b and 5b2?

The GCF is 5b.


How do you factorize 4a2-20ab2 plus 25b4?

4a2 - 20ab2 + 25b4 (2a - 5b2)(2a - 5b2) (2a - 5b2)2


Factor b3 - 5b2 plus 12?

b3 - 5b2 + 12 = (b - 2)(b2 - 3b - 6)Check:(b - 2)(b2 - 3b - 6)= b(b2 - 3b - 6) - 2(b2 - 3b - 6)= b3 - 3b2 - 6b - 2b2 + 6b + 12= b3 - 5b2 + 12


How do you factor -5b2 plus 7b-2?

It is: (-5b+2)(b-1) with the help of the quadratic equation formula


What is factored form of 5a squared-20ab-25b squared?

5a2 - 20ab - 25b2 = 5(a2 - 4ab - 5b2) = 5(a2 - 4ba - 5b2) since -5b*b = -5b2 and -5b + b = -4b, then = 5(a - 5b)(a + b)


Simplify 3b5a 3b 4-3ab 5b2?

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How do you solve 5b squared equals 8b?

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Prove that root of 5 is irrational?

Suppose we start with the opposite view. That is, the square root of 5 is rational. This means that it can be expressed as a ratio of two integers. Let the square root of 5 in its simplest terms be a/b so that a and b are integers with no common factors and b > 0.sqrt(5) = a/b so 5 = a2/b2that is, 5b2= a25 is a factor of the left hand side (LHS) so 5 must be a factor of the right hand side (RHS).Since 5 is a prime and a is an integer, 5 must be a factor of a. That is, a = 5c for some integer c and since a and b are coprime b and c must also be coprime.But now,5 = (5c)2/b2so that 5 = 25c2/b2and so b2= 5c2. As before, this implies that 5 must be a factor of b. But that contradicts the supposition that a and b are coprime.The contradiction implies that the original assumption was incorrect. That is, sqrt(5) cannot be rational.


1 2a3-1 2a3-5b2?

Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals", "squared".


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