The greatest number of intersection points that four coplanar lines can have occurs when no two lines are parallel and no three lines intersect at the same point. In this case, the maximum number of intersection points can be calculated using the formula ( \frac{n(n-1)}{2} ), where ( n ) is the number of lines. For four lines, this results in ( \frac{4(4-1)}{2} = 6 ) intersection points.
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The greatest number of intersection points with just four lines is 6.
The greatest number is six.
100*99/2 = 4950
Coplanar Points are points that lie on the same line.
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6! Thank you to ChaCha Answers. Wiki sucks, compared to ChaCha. :) -Geometry Student from TX
The greatest number of intersection points with just four lines is 6.
The greatest number is six.
6*5/2 = 15.
100*99/2 = 4950
non-coplanar points
They need not be. The four vertices of a quadrilateral are coplanar but NOT collinear. On the other hand, any line (in Eucledian geometry) has an infinite number of points on it - all of which are coplanar.
Coplanar Points are points that lie on the same line.
3 coplanar points may or may not be collinear. 3 collinear points must be coplanar.
No, a line cannot contain four non-coplanar points. By definition, coplanar points are points that lie in the same plane, and any three points determine a plane. Since a line consists of an infinite number of points that are linear, any additional point beyond two points on a line will not be able to create a non-coplanar arrangement with those already on the line. Thus, four points on a line must be coplanar.
Points that are coplanar are on the same plane.