The greatest number of intersection points with just four lines is 6.
100*99/2 = 4950
The greatest number is six.
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The greatest number of intersection points that four coplanar lines can have occurs when no two lines are parallel and no three lines intersect at the same point. In this case, the maximum number of intersection points can be calculated using the formula ( \frac{n(n-1)}{2} ), where ( n ) is the number of lines. For four lines, this results in ( \frac{4(4-1)}{2} = 6 ) intersection points.
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100*99/2 = 4950
The greatest number is six.
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6 maximum points of intersection
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If the points are collinear, the number of possible planes is infinite. If the points are not collinear, the number of possible planes is ' 1 '.
discuss the possible number of points of interscetion of two distinct circle
The smallest number of points of intersection of five lines drawn in a plane occurs when all the lines are parallel. In this case, the lines do not intersect at all, resulting in zero points of intersection. Thus, the smallest number of points of intersection is 0.
please answer
No.
Greatest possible number of intersections for following lines:1(line(s)) = 0 (intersections)2= 13= 1+24= 1+2+35= 1+2+3+4....8=1+2+3+4+5+6+7= 28Every time you add a line, you are able to create 1 more maximum intersection than the previous state. You can add up until 'number of lines - (minus) 1'.
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