answersLogoWhite

0

The smallest number of points of intersection of five lines drawn in a plane occurs when all the lines are parallel. In this case, the lines do not intersect at all, resulting in zero points of intersection. Thus, the smallest number of points of intersection is 0.

User Avatar

AnswerBot

4mo ago

What else can I help you with?

Related Questions

What is the greatest number of points of intersection that can occur when 2 different circles and 2 different straight lines are drawn on the same piece of paper?

please answer


What is the difference between radiation and intersection?

Radiation is suitable for locating the objects from a single point , while Intersection is suitable for the inaccessible points by intersection of rays drawn from two instrument stations.


How many planes can be drawn between two district points?

Between 2 distinct points, there are an infinite number of planes that can be drawn in 3 dimensions


What is the minimum number of points through which a line is drawn?

A line is defined by at least two distinct points. Therefore, the minimum number of points through which a line can be drawn is two. These two points determine the direction and position of the line in a two-dimensional space.


How many lines can be drawn to a given points?

Through any two distinct points, exactly one straight line can be drawn. If you have more than two points, the number of lines that can be drawn depends on how many of those points are distinct and not collinear. For ( n ) distinct points, the maximum number of lines that can be formed is given by the combination formula ( \binom{n}{2} ), which represents the number of ways to choose 2 points from ( n ). If some points are collinear, the number of unique lines will be less.


How many points can be drawn from one point?

No points can be drawn from a point.


How many straight lines can be drawn using 8 non collinear points?

From 8 non-collinear points, the number of straight lines that can be drawn is determined by choosing any two points to form a line. This can be calculated using the combination formula ( \binom{n}{r} ), where ( n ) is the total number of points and ( r ) is the number of points to choose. For 8 points, the calculation is ( \binom{8}{2} = \frac{8 \times 7}{2 \times 1} = 28 ). Therefore, 28 straight lines can be drawn using 8 non-collinear points.


If 20 points are placed on a circle and every pair of points are joined with a line segment what is the total number of segments drawn?

twenty


How do you determine the number of segments that can be drawn connecting each pair of points?

If there are n points then the maximum number of lines possible is n*(n-1)/2 and that maximum is attained of no three points are collinear.


Given n points in the plane you draw all possible triangles whose vertices are any three of the given points Atleast how many of them are obtuse-angled triangles?

The least number of obtuse triangles, if all possible triangles are drawn for n points in a plane, is zero. If all the n points lie in a straight line, no triangles are possible and so no obtuse triangles are able to be drawn; thus for any number n, there is a possibility that no obtuse triangles can be drawn, so the least possible number of obtuse triangles drawn is zero.


How many lines can be drawn from n number of points?

5 x 5 equels 10


How many planes can be drawn when three distinct points are collinear?

If the points are collinear, that means there's only one straight line. An infinite number of different planes can be drawn that contain one straight line.