To solve the inequality ( 8.904x < 18.037 ), we first isolate ( x ) by dividing both sides by 8.904. This gives us ( x < \frac{18.037}{8.904} ), which approximately equals 2.022. The greatest possible integer solution is therefore ( x = 2 ).
To find the least possible integer solution of the inequality (4.10 < 3x < 19.86), we first solve for (x) by dividing the entire inequality by 3. This gives us (1.3667 < x < 6.62). The least integer greater than (1.3667) is (2). Therefore, the least possible integer solution is (2).
The inequality ( x^3 < 3 ) can be solved by finding the integer values of ( x ) that satisfy this condition. To do this, we first note that ( x^3 = 3 ) has a real solution at ( x = \sqrt[3]{3} \approx 1.442 ). The integer solutions for the inequality ( x^3 < 3 ) are thus ( x = -2, -1, 0, 1 ). Therefore, the integer solutions are ( x \in {-2, -1, 0, 1} ).
When you divide or multiply both sides of an inequality by a negative integer, the inequality sign must be reversed. For example, if you have the inequality (a < b) and you divide both sides by a negative number, the resulting inequality will be (a / (-n) > b / (-n)), where (n) is a positive integer. This reversal is necessary to maintain the truth of the inequality.
Since the number is given to an integer, the answer is 0.5 metres.
To find the integer solutions of the inequality ( x^2 < n ) (where ( n ) is a positive integer), first determine the square root of ( n ). The integer solutions for ( x ) will be all integers satisfying ( -\sqrt{n} < x < \sqrt{n} ). This means you consider all integers from ( -\lfloor \sqrt{n} \rfloor ) to ( \lfloor \sqrt{n} \rfloor ), excluding the endpoints if ( n ) is a perfect square.
To find the least possible integer solution of the inequality (4.10 < 3x < 19.86), we first solve for (x) by dividing the entire inequality by 3. This gives us (1.3667 < x < 6.62). The least integer greater than (1.3667) is (2). Therefore, the least possible integer solution is (2).
The inequality ( x^3 < 3 ) can be solved by finding the integer values of ( x ) that satisfy this condition. To do this, we first note that ( x^3 = 3 ) has a real solution at ( x = \sqrt[3]{3} \approx 1.442 ). The integer solutions for the inequality ( x^3 < 3 ) are thus ( x = -2, -1, 0, 1 ). Therefore, the integer solutions are ( x \in {-2, -1, 0, 1} ).
17 is not an equation and so there can be no "solution of 17". There is, therefore, no possible answer to the question.
The greatest possible 'length' comes from the number with the greatest number of prime factors. The greatest number of factors is created by using the smallest prime number, 2, as a factor as many times as possible. Since 2^9=512 and 2^10=1024, the greatest possible 'length' of a positive integer less than 1000 is 9.
When you divide or multiply both sides of an inequality by a negative integer, the inequality sign must be reversed. For example, if you have the inequality (a < b) and you divide both sides by a negative number, the resulting inequality will be (a / (-n) > b / (-n)), where (n) is a positive integer. This reversal is necessary to maintain the truth of the inequality.
Since the number is given to an integer, the answer is 0.5 metres.
No, because there is no greatest integer.
The smallest positive integer is 1. 1 is the multiplicative identity; ie anything times 1 is itself. The greatest negative integer is the most positive negative integer which is -1. Therefore the product of the greatest negative integer and the smallest positive integer is the greatest negative integer which is -1.
To find the integer solutions of the inequality ( x^2 < n ) (where ( n ) is a positive integer), first determine the square root of ( n ). The integer solutions for ( x ) will be all integers satisfying ( -\sqrt{n} < x < \sqrt{n} ). This means you consider all integers from ( -\lfloor \sqrt{n} \rfloor ) to ( \lfloor \sqrt{n} \rfloor ), excluding the endpoints if ( n ) is a perfect square.
There is no greatest integer. Whatever integer you think is greatest, you can always add one (1) to it and get a larger one.
The greatest factor of any integer is the integer itself.
The greatest factor of any integer is the integer itself.