4 & |-4|
Since the smallest integer is 2, the largest one let be x. At least 12 means equal to 12 or larger than 12. So we have this inequality: x - 2 ≥ 12 x - 2 + 2 ≥ 12 + 2 x ≥ 14
x = 484
3 x - 7 = -21
Multiply the 4 smallest prime numbers... 2 X 3 X 5 X 7 = 210
Suppose x = sqrt(3*a) where a is an integer that is not divisible by 3. then x2 = 3*a which is divisible by 3. but x is not even rational and so is not an integer and is certainly not divisible by 3.
The inequality ( x^3 < 3 ) can be solved by finding the integer values of ( x ) that satisfy this condition. To do this, we first note that ( x^3 = 3 ) has a real solution at ( x = \sqrt[3]{3} \approx 1.442 ). The integer solutions for the inequality ( x^3 < 3 ) are thus ( x = -2, -1, 0, 1 ). Therefore, the integer solutions are ( x \in {-2, -1, 0, 1} ).
The inequality ( x < 3 ) includes all integer solutions that are less than 3. Therefore, the integer solutions are ( \ldots, -2, -1, 0, 1, 2 ). In interval notation, this can be expressed as ( (-\infty, 3) ) for the integers.
To find the integer solutions of the inequality ( x^2 < n ) (where ( n ) is a positive integer), first determine the square root of ( n ). The integer solutions for ( x ) will be all integers satisfying ( -\sqrt{n} < x < \sqrt{n} ). This means you consider all integers from ( -\lfloor \sqrt{n} \rfloor ) to ( \lfloor \sqrt{n} \rfloor ), excluding the endpoints if ( n ) is a perfect square.
It seems there's a part of your question missing regarding the specific inequality involving ( x ). However, if you're referring to a general inequality like ( x > 0 ), the graph would consist of all points on the number line to the right of the origin (0), representing all positive integer solutions: ( 1, 2, 3, \ldots ). If you provide the specific inequality, I can give a more tailored response!
x - 3 is not an inequality.
What is the inequality of: x - 4 < 6
To find the least possible integer solution of the inequality (4.10 < 3x < 19.86), we first solve for (x) by dividing the entire inequality by 3. This gives us (1.3667 < x < 6.62). The least integer greater than (1.3667) is (2). Therefore, the least possible integer solution is (2).
The statement "X0" is unclear, but if you are referring to an inequality such as x > 0 or x ≤ 0, it indicates that there are infinite solutions within the specified range. For instance, if the inequality is x > 0, the solutions include all positive real numbers. These solutions can be represented on a number line or in interval notation, such as (0, ∞) for x > 0.
The equation ( x = 14 ) identifies a single integer solution, which is ( x = 14 ) itself. Since the equation specifies that ( x ) is equal to 14, there are no other integer solutions. Therefore, the only integer solution is ( {14} ).
To solve the inequality (8x^2 - x < 0), we first factor it as (x(8x - 1) < 0). The critical points are (x = 0) and (x = \frac{1}{8}). Analyzing the sign of the product in the intervals determined by these points, we find that the inequality holds for (0 < x < \frac{1}{8}). Since there are no integer values of (x) in this interval, the number of different integer values of (x) that satisfy the inequality is zero.
To determine a solution to an inequality, you need to specify the inequality itself. Solutions vary depending on the inequality's form, such as linear (e.g., (x > 3)) or quadratic (e.g., (x^2 < 4)). Once the inequality is provided, you can identify specific numbers that satisfy it. Please provide the inequality for a precise solution.
x2 = 16take the root square for both sides the result will be :X = +4 or -4