4 & |-4|
Since the smallest integer is 2, the largest one let be x. At least 12 means equal to 12 or larger than 12. So we have this inequality: x - 2 ≥ 12 x - 2 + 2 ≥ 12 + 2 x ≥ 14
x = 484
3 x - 7 = -21
Multiply the 4 smallest prime numbers... 2 X 3 X 5 X 7 = 210
Suppose x = sqrt(3*a) where a is an integer that is not divisible by 3. then x2 = 3*a which is divisible by 3. but x is not even rational and so is not an integer and is certainly not divisible by 3.
The inequality ( x^3 < 3 ) can be solved by finding the integer values of ( x ) that satisfy this condition. To do this, we first note that ( x^3 = 3 ) has a real solution at ( x = \sqrt[3]{3} \approx 1.442 ). The integer solutions for the inequality ( x^3 < 3 ) are thus ( x = -2, -1, 0, 1 ). Therefore, the integer solutions are ( x \in {-2, -1, 0, 1} ).
The inequality ( x < 3 ) includes all integer solutions that are less than 3. Therefore, the integer solutions are ( \ldots, -2, -1, 0, 1, 2 ). In interval notation, this can be expressed as ( (-\infty, 3) ) for the integers.
To find the integer solutions of the inequality ( x^2 < n ) (where ( n ) is a positive integer), first determine the square root of ( n ). The integer solutions for ( x ) will be all integers satisfying ( -\sqrt{n} < x < \sqrt{n} ). This means you consider all integers from ( -\lfloor \sqrt{n} \rfloor ) to ( \lfloor \sqrt{n} \rfloor ), excluding the endpoints if ( n ) is a perfect square.
It seems there's a part of your question missing regarding the specific inequality involving ( x ). However, if you're referring to a general inequality like ( x > 0 ), the graph would consist of all points on the number line to the right of the origin (0), representing all positive integer solutions: ( 1, 2, 3, \ldots ). If you provide the specific inequality, I can give a more tailored response!
x - 3 is not an inequality.
What is the inequality of: x - 4 < 6
The statement "X0" is unclear, but if you are referring to an inequality such as x > 0 or x ≤ 0, it indicates that there are infinite solutions within the specified range. For instance, if the inequality is x > 0, the solutions include all positive real numbers. These solutions can be represented on a number line or in interval notation, such as (0, ∞) for x > 0.
The equation ( x = 14 ) identifies a single integer solution, which is ( x = 14 ) itself. Since the equation specifies that ( x ) is equal to 14, there are no other integer solutions. Therefore, the only integer solution is ( {14} ).
To find the least possible integer solution of the inequality (4.10 < 3x < 19.86), we first solve for (x) by dividing the entire inequality by 3. This gives us (1.3667 < x < 6.62). The least integer greater than (1.3667) is (2). Therefore, the least possible integer solution is (2).
To solve the inequality (8x^2 - x < 0), we first factor it as (x(8x - 1) < 0). The critical points are (x = 0) and (x = \frac{1}{8}). Analyzing the sign of the product in the intervals determined by these points, we find that the inequality holds for (0 < x < \frac{1}{8}). Since there are no integer values of (x) in this interval, the number of different integer values of (x) that satisfy the inequality is zero.
To determine a solution to an inequality, you need to specify the inequality itself. Solutions vary depending on the inequality's form, such as linear (e.g., (x > 3)) or quadratic (e.g., (x^2 < 4)). Once the inequality is provided, you can identify specific numbers that satisfy it. Please provide the inequality for a precise solution.
x2 = 16take the root square for both sides the result will be :X = +4 or -4