If the numbers are positive integers then the maximum product is usually obtained when the three numbers are equal but this cannot apply in this case.
However, the three numbers that are almost equal are 7,7 and 6.
The maximum product is, 7 x 7 x 6 = 294.
Highest 2-digit number = 99 Highest 1-digit number = 9 Highest possible sum from 2, 2-digit numbers = 198 Highest possible sum from 2, 1-digit numbers = 18
Not possible in whole numbers
It is impossible for the product of two prime numbers to be prime. It is impossible for the sum of two prime numbers to be prime as long as one of the numbers isn't 2.
This is mathematically impossible. The highest product that you can get with two numbers that make thirteen is 42 (7*6). The lowest sum you can get for two numbers with a product of 155 is 36 (31 and 5). All in all, it's impossible.
900 - 30 times 30
Highest 2-digit number = 99 Highest 1-digit number = 9 Highest possible sum from 2, 2-digit numbers = 198 Highest possible sum from 2, 1-digit numbers = 18
Not possible in whole numbers
41
Their product.
It is impossible for the product of two prime numbers to be prime. It is impossible for the sum of two prime numbers to be prime as long as one of the numbers isn't 2.
No - the product of numbers is the answer to a multiplication sum, while the sum of numbers is the answer to an addition sum.
This is mathematically impossible. The highest product that you can get with two numbers that make thirteen is 42 (7*6). The lowest sum you can get for two numbers with a product of 155 is 36 (31 and 5). All in all, it's impossible.
272 is the maximum possible.
i'll... say both?highest: 99+99+99=297lowest: 10+10+10=30
Two numbers have a product of 80 their sum is 24?
For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.
If the sum of 2 numbers is 25 and their product is 156, the numbers are 12 and 13.