If the numbers are positive integers then the maximum product is usually obtained when the three numbers are equal but this cannot apply in this case.
However, the three numbers that are almost equal are 7,7 and 6.
The maximum product is, 7 x 7 x 6 = 294.
Highest 2-digit number = 99 Highest 1-digit number = 9 Highest possible sum from 2, 2-digit numbers = 198 Highest possible sum from 2, 1-digit numbers = 18
Not possible in whole numbers
It is impossible for the product of two prime numbers to be prime. It is impossible for the sum of two prime numbers to be prime as long as one of the numbers isn't 2.
This is mathematically impossible. The highest product that you can get with two numbers that make thirteen is 42 (7*6). The lowest sum you can get for two numbers with a product of 155 is 36 (31 and 5). All in all, it's impossible.
900 - 30 times 30
Highest 2-digit number = 99 Highest 1-digit number = 9 Highest possible sum from 2, 2-digit numbers = 198 Highest possible sum from 2, 1-digit numbers = 18
Not possible in whole numbers
41
Their product.
It is impossible for the product of two prime numbers to be prime. It is impossible for the sum of two prime numbers to be prime as long as one of the numbers isn't 2.
272 is the maximum possible.
This is mathematically impossible. The highest product that you can get with two numbers that make thirteen is 42 (7*6). The lowest sum you can get for two numbers with a product of 155 is 36 (31 and 5). All in all, it's impossible.
i'll... say both?highest: 99+99+99=297lowest: 10+10+10=30
NO!!! Product means Mu;ltiply Sum means Addition (Add).
10, -9 sum is 1 product is -90. any two numbers one positive one negative, positive has to be larger
the product of 3 whole numbers is 5. Their sum is 7. what are the numbers
For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.