For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.
find two positive numbers whose product is a maximum. 1.) the sum is s.
5+5 = 10 (Sum is ten)5*5 = 25 (Product is 25)*this product is maximum for all any 2 real numbers that == 10
The numbers are 13 and 8 The product is 104
Assuming the two numbers must be positive whole numbers, the answer is 1 and 11. If they need to be non-negative, it is 0 and 12. If negative numbers are permitted (eg -1 and 13) there is no limit to the sum - ie there is no maximum.
For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.
the product of 3 whole numbers is 5. Their sum is 7. what are the numbers
find two positive numbers whose product is a maximum. 1.) the sum is s.
3844
"The sum of a number and three times another number is 18. find the numbers if their product is a maximum?"
64
Not possible in whole numbers
Not whole numbers, no.
5+5 = 10 (Sum is ten)5*5 = 25 (Product is 25)*this product is maximum for all any 2 real numbers that == 10
the two numbers can only be 24 and24
-8x-8=64
They are 12 and 15