+19/-0 micrometres for H6 over 50mm up to 80mm dia
1000 mm = 1 m so 70 mm = 70/1000 = 0.07 metres. Simple!
10 mm = 1 cm 20 mm = 2 cm 30 mm = 3 cm . . 70 mm = 7 cm
The tolerance for a 130 H7 hole specifies the permissible limits of its size. For a hole with a nominal diameter of 130 mm and a tolerance grade of H7, the hole's upper limit is 130 mm and the lower limit is 130 mm minus 0.021 mm, resulting in a tolerance range of 130.000 mm to 129.979 mm. This means the hole can be between these two measurements to maintain its H7 designation.
The tolerance for a diameter 10H12 hole indicates that the hole is specified with a nominal diameter of 10 mm and a tolerance class of H12. In this case, the "H" signifies that the hole is a basic hole, and the "12" denotes the tolerance grade, which typically corresponds to a specific range of permissible diameters. For a 10H12 hole, the upper limit is 10.025 mm and the lower limit is 10.000 mm, allowing for a tolerance of +0.025 mm.
About this big - |.......................................................................|
H6 tolerance for 95 mm hole is +0.022/0
Tolerance H6 for a dimension of 1250 mm indicates a specific range of allowable deviation for that measurement. The "H" signifies a hole fit tolerance, and the "6" refers to a specific tolerance grade. For a nominal dimension of 1250 mm, the tolerance would typically be between -0.025 mm and 0 mm, meaning the actual measurement can be as small as 1249.975 mm but not exceed 1250 mm. This ensures a precise fit in engineering applications.
10H7 (Hole!- negative cote) (biggest) is from +10,018 to +10,000 tolerance. 10h7 (shaft - positive cote) is from +10,000 to +9,982 tolerance.
70 µm = 0.07 mm
I came across the same question myself. The plug hole is on the radiator side of the engine behind the exhaust. Mine was a size 14 mm bolt.
1000 mm = 1 m so 70 mm = 70/1000 = 0.07 metres. Simple!
There are 20 millimeters between 50 mm and 70 mm. This is calculated by subtracting 50 mm from 70 mm, which equals 20 mm. Therefore, the range between these two measurements contains 20 mm.
S=16T/pi()d^3 70N/mm^2=16*(1 x 10^6 N-mm)/(pi()*d^3) d = 41.75mm
10 mm = 1 cm 20 mm = 2 cm 30 mm = 3 cm . . 70 mm = 7 cm
There are 10 millimetres in a centimetre. You need to multiply cm by 10. Therefore 7*10 is 70 millimetres.
The tolerance for a 130 H7 hole specifies the permissible limits of its size. For a hole with a nominal diameter of 130 mm and a tolerance grade of H7, the hole's upper limit is 130 mm and the lower limit is 130 mm minus 0.021 mm, resulting in a tolerance range of 130.000 mm to 129.979 mm. This means the hole can be between these two measurements to maintain its H7 designation.
25.4 mm = 1 in →70 mm = 70 ÷ 25.4 in ≈ 2.76 in