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How do you calculate acceleration when given velocity and distance?
v2 - u2 = 2as so that a = (v2 - u2)/2s where u = initial velocity v = final velocity s = distance a = acceleration
If your null hypothesis is Ho u1 equals u2?
yes.
After stopping at a station a train accelerates at a steady rate of 0.25ms-2 At what speed is the train moving after it has traveled 1.0 km?
Using v2 - u2 = 2as where, v = final velocity u = initial velocity a = acceleration s = distance travelled we get v2 = u2 + 2as Substituting the values, we get v2 = 02 + (2 x 0.25 x 1000) so v2 = 500, therefore v = 22.36 The train will be travelling at 22.36 ms-1.
What speed must an object leave the ground to travel 2.5 meters up?
Using the physics formula: v2 = u2 + 2as v - final velocity u - initial velocity a - acceleration s - distance When the object leaves the ground it is being slowed down by gravity until it stops so the acceleration equals -9.8m/s2 and as it will stop at 2.5 meters v = 0. U is the value we want to find out: 02 = u2 + (2 *-9.8*2.5) 49 = u2 So the object must leave the ground at 7m/s. By the way this is ignoring air resistance.
What factors are involved in determining stopping distance of a toy car?
arent u a science student? its simple. time,initial velocity,accelaration the formula is; v2=u2+2as here v is final velocity u is innitial velocity a is accelaration s will be3 the stopping distance okkkk!!
How do you calculate acceleration when given velocity and distance?
v2 - u2 = 2as so that a = (v2 - u2)/2s where u = initial velocity v = final velocity s = distance a = acceleration
If your null hypothesis is Ho u1 equals u2?
yes.
After stopping at a station a train accelerates at a steady rate of 0.25ms-2 At what speed is the train moving after it has traveled 1.0 km?
Using v2 - u2 = 2as where, v = final velocity u = initial velocity a = acceleration s = distance travelled we get v2 = u2 + 2as Substituting the values, we get v2 = 02 + (2 x 0.25 x 1000) so v2 = 500, therefore v = 22.36 The train will be travelling at 22.36 ms-1.
What is the LCM of u2-1and u2 plus 9u plus 8?
The LCM is u3 + 8u2 - u - 8u2 - 1 = (u -1)(u + 1)u2 + 9u + 8 = (u + 8)(u + 1)Thus, the LCM = (u - 1)[(u + 1)(u + 8)] = (u - 1)(u2 + 9u + 8).
What speed must an object leave the ground to travel 2.5 meters up?
Using the physics formula: v2 = u2 + 2as v - final velocity u - initial velocity a - acceleration s - distance When the object leaves the ground it is being slowed down by gravity until it stops so the acceleration equals -9.8m/s2 and as it will stop at 2.5 meters v = 0. U is the value we want to find out: 02 = u2 + (2 *-9.8*2.5) 49 = u2 So the object must leave the ground at 7m/s. By the way this is ignoring air resistance.
A ball is thrown vertically upwards with velocity of 19.6ms what is the maximum height to which it will reach?
apply the formula: v2 - u2 = 2as. Here v= 0; u = 19.6m/s; a = -g ,find s and that's max. heigth
How do you factor completely u2-2u plus 1?
u2 - 2u +1 = u2 - u - u + 1 = u*(u - 1) - 1*(u - 1) = (u - 1)*(u - 1) = (u - 1)2
Who are U2?
U2 is a pop band
What factors are involved in determining stopping distance of a toy car?
arent u a science student? its simple. time,initial velocity,accelaration the formula is; v2=u2+2as here v is final velocity u is innitial velocity a is accelaration s will be3 the stopping distance okkkk!!
What country did the u2 form?
U2 is from Dublin
Who is the leader of U2?
Theres no leader of U2
What is the final speed of a bullet train accelerating at a rate of 200 kilometer per hour from an initial speed of 150 kilometer per hour over a distance of 100 km?
v2 = u2 + 2as = 1502 + 2*200*100 = 62500 So v = 250 km per hour
