Could you please provide more context or information regarding the variable "b"? Without additional details or a specific equation or problem, I cannot determine the integer value for b.
Yes, if the first integer (let's call it ( a )) is greater than the second integer (let's call it ( b )), then the opposite (or negative) of the first integer (-( a )) will indeed be less than the opposite of the second integer (-( b )). This is because negating both integers reverses their order; since ( a > b ), it follows that -( a < -b ).
In mathematics, a multiple of an integer is the product of that integer with another integer. In other words, a is a multiple of b if a = nb, where nis an integer. If b is not zero, this is equivalent to saying that a / b is an integer.0 is a multiple of every integer ().Source: http://en.wikipedia.org/wiki/Multiple_(mathematics)
The quotient of two integers is another integer when the divisor (the second integer) divides the dividend (the first integer) evenly, meaning there is no remainder. In mathematical terms, if ( a ) and ( b ) are integers, ( a \div b ) is an integer if ( b \neq 0 ) and ( a ) is a multiple of ( b ). For example, ( 6 \div 2 = 3 ) is an integer, while ( 7 \div 2 ) is not.
To subtract one integer from another, you can use the concept of adding the opposite. For example, to compute ( a - b ), you can instead add the negative of ( b ) to ( a ): ( a + (-b) ). This effectively shifts the value of ( a ) in the direction indicated by ( b ), resulting in the correct difference.
To subtract an integer from another integer, you can convert the subtraction into addition by changing the sign of the integer being subtracted. For example, to calculate ( a - b ), you can instead compute ( a + (-b) ). This approach allows you to combine the values directly, ensuring you maintain the correct sign based on the magnitudes of ( a ) and ( b ). Finally, simply perform the addition to arrive at the result.
In mathematics, a multiple of an integer is the product of that integer with another integer. In other words, a is a multiple of b if a = nb, where nis an integer. If b is not zero, this is equivalent to saying that a / b is an integer.0 is a multiple of every integer ().Source: http://en.wikipedia.org/wiki/Multiple_(mathematics)
If a and b are integers, then a times b is an integer.
The quotient of two integers is another integer when the divisor (the second integer) divides the dividend (the first integer) evenly, meaning there is no remainder. In mathematical terms, if ( a ) and ( b ) are integers, ( a \div b ) is an integer if ( b \neq 0 ) and ( a ) is a multiple of ( b ). For example, ( 6 \div 2 = 3 ) is an integer, while ( 7 \div 2 ) is not.
dim a as integer dim b as integer dim c as integer dim d as integer private sub command1_click () a=-1 b=1 d=1 while (d<=10) c=a+b print c a=b b=c next d end sub
It is a number that can be expressed as a fraction but is NOT an integer. For example. 3 is an integer and it is rational since we can write 3/1, but 1/3 is not an integer and it is rational since we wrote it as a fraction or a ratio. Remember that a rational number is one that can be written as A/B where A and B are integers. Now if B is 1, which is certainly an integer, A/1 is rational but since A is an integer, A/1 is an integer.
An even integer is a multiple of 2 so that if x is the even integer then there is some other integer a such that x = 2a. An odd integer is one which, when you divide it by 2, leaves a remainder of 1. That is, if y is the odd integer, then y = 2b + 1 for some other integer b. Now, the sum of the even and odd integer is x + y = 2a + 2b + 1 = 2(a+b) + 1 By the closure of integers under addition, a and b are integers implies that a+b is an integer. So 2(a+b) is even and so the sum is odd.
Because a is rational, there exist integers m and n such that a=m/n. Because b is rational, there exist integers p and q such that b=p/q. Consider a+b. a+b=(m/n)+(p/q)=(mq/nq)+(pn/mq)=(mq+pn)/(nq). (mq+pn) is an integer because the product of two integers is an integer, and the sum of two integers is an integer. nq is an integer since the product of two integers is an integer. Because a+b equals the quotient of two integers, a+b is rational.
If A and B are multiples of C, then A + B is also a multiple of C: If A is a multiple of C then A = mC for some integer m If B is a multiple of C, then B = nC for some integer n → A + B = mC + nC = (m + n)C = kC where k = m + n and is an integer → A + B is a multiple of C
A-b
A factor of a integer is an integer that divides the second integer into a third integer exactly; i.e. A is a factor of B if B/A is exactly C, where all of A, B and C are integers. A prime factor is a factor as above, but is also a prime number. This means that the only factors of that factor are one and the number itself; i.e. A is a prime factor of B if B/A is exactly C andthe only factors of A are 1 and A.
Subtraction a-b
If a is even then there is an integer x such that a = 2x If b is even then there is an integer y such that b = 2y Then a+b = 2x+2y = 2(x+y) ie 2 is a factor of a+b, that is, a+b is even.