Int (e^(-x^2)) = Int (1 + (-x^2) + (-x^2)^2/2! + (-x^2)^3/3! + ...
= x - x^3/3 + x^5/(5*2!) - x^7/(7*3!) ...
which, if taken with limits of integration from negative infinity to infinity, solves to the square root of x, making it one of the most famous and beautiful formulas in math.
maths signs
The integral of (-e^x) with respect to (x) is (-e^x + C), where (C) is the constant of integration. This represents the family of functions whose derivative is (-e^x).
if you take your time youll figure out its e=mc2
tan(sqrtX) + C
x is negative 1x is negative 2
maths signs
The integral of (-e^x) with respect to (x) is (-e^x + C), where (C) is the constant of integration. This represents the family of functions whose derivative is (-e^x).
-e^(-x) or negative e to the negative x this is because you multiply the function (e) by: 1 / (the derivative of the power ... in this case: -1) e^(-x) * (1/-1) = -e^(-x) Don't forget to add your constant!
-cotan(x)
integral of radical sinx
integral of e to the power -x is -e to the power -x
The indefinite integral of (1/x^2)*dx is -1/x+C.
Well, honey, when you multiply x by negative x, you get negative x squared. It's like math's way of saying "two wrongs don't make a right, they make a negative." So, in this case, x times negative x equals negative x squared.
arctan(x)
.5(x-sin(x)cos(x))+c
if you take your time youll figure out its e=mc2
the integral of the square-root of (x-1)2 = x2/2 - x + C