Int (e^(-x^2)) = Int (1 + (-x^2) + (-x^2)^2/2! + (-x^2)^3/3! + ...
= x - x^3/3 + x^5/(5*2!) - x^7/(7*3!) ...
which, if taken with limits of integration from negative infinity to infinity, solves to the square root of x, making it one of the most famous and beautiful formulas in math.
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if you take your time youll figure out its e=mc2
tan(sqrtX) + C
x is negative 1x is negative 2
Use integration by parts. integral of xe^xdx =xe^x-integral of e^xdx. This is xe^x-e^x +C. Check by differentiating. We get x(e^x)+e^x(1)-e^x, which equals xe^x. That's it!