arctan(x)
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(5x 2 - 8x + 1) + (2x 2 - 4x - 11)
∫1/(1-x)2dxWe can rewrite the integral as ∫(1-x)-2dx.Thus:∫(1-x)-2dxu = 1-xdu = -1-1∫-1(1-x)-2dx-1∫u-2du(u-1|0u=1-x(1-x)-1So we conclude that ∫1/(1-x)2dx = (1-x)-1 or 1/(1-x)
2(x + 3)(x + 1)
4
yes 1 + cot x^2 = csc x^2