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Earn +20 ptsQ: What is the integral of 1 divided by x squared?
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What is the integral of x divided by x plus 1?
x/(x+1) = 1 - 1/(x + 1), so the antiderivative (or indefinite integral) is x + ln |x + 1| + C,
What is the definite integral of 1 divided by x squared?
For it to be a definite integral, you would need to specify a range. We can however give you the indefinite integral. The easiest way to do this is to think of it not as a fraction, but as a negative exponent: 1/x2 = x-2 It then becomes quite easy to integrate, as we can say in general: ∫(axn) dx = ax(n + 1) / (n + 1) + C In this case then, we have: ∫(x-2) dx = -x-1 + C, or -1/x + C
What is the integral of 1 divided by xln2x?
0.5
Integral of sec squared radical x?
integral of radical sinx
What is the integral of cot squared x?
ln(sinx) + 1/3ln(sin3x) + C
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