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Q: What is the integral of 1 divided by x squared?

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There can be no definite integral because the limits of integration are not specified. The indefinite integral of 1/x2 is -1/x + C

x/(x+1) = 1 - 1/(x + 1), so the antiderivative (or indefinite integral) is x + ln |x + 1| + C,

0.5

integral of radical sinx

ln(sinx) + 1/3ln(sin3x) + C

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There can be no definite integral because the limits of integration are not specified. The indefinite integral of 1/x2 is -1/x + C

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the integral of the square-root of (x-1)2 = x2/2 - x + C

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1. Anything divided by itself always equals 1.

x/(x+1) = 1 - 1/(x + 1), so the antiderivative (or indefinite integral) is x + ln |x + 1| + C,

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