2, 3, 5, And 7 are the first 4 prime numbers
No.
1, 3, 9, 1009, 3027, 9081 3 and 1009 are prime.
1155
it is 3
2, 3, 5, And 7 are the first 4 prime numbers
It is 1.
Well, isn't that a happy little math problem! When we look at the unit digit of powers of numbers, we focus on the cyclical pattern they follow. The unit digit of 3 raised to any power follows a pattern: 3, 9, 7, 1, and then repeats. So, to find the unit digit of 3 to the power of 34 factorial, we look for the remainder when 34 factorial is divided by 4, which is 2. Therefore, the unit digit of 3 to the power of 34 factorial is 9.
To find the last digit of 373^333, we need to look for a pattern in the units digit of the powers of 3. The units digit of powers of 3 cycles every 4 powers: 3^1 = 3, 3^2 = 9, 3^3 = 7, 3^4 = 1, and then it repeats. Since 333 is one less than a multiple of 4, the units digit of 3^333 will be the third number in the cycle, which is 7. Therefore, the last digit of 373^333 is 7.
this is a guess and check problem. answers is 1009. 999 - 10 = 989 lets try one less (998) 998 -9(1 digit) is not possible, lets try one more (1000) 1000(4 digit) - 11 is not possible so only possible solution is (999,10) Answers is 999+10 = 1009
No.
1, 3, 9, 1009, 3027, 9081 3 and 1009 are prime.
1155
3
3
it is 3
1