2, 3, 5, And 7 are the first 4 prime numbers
No.
1, 3, 9, 1009, 3027, 9081 3 and 1009 are prime.
1155
it is 3
2, 3, 5, And 7 are the first 4 prime numbers
To find the last digit of a number raised to a power, we can use the concept of modular arithmetic. The last digit of 333 to the power of 444 can be determined by finding the remainder when 333 is divided by 10, which is 3. Since the last digit of 333 is 3, we need to find the remainder of 444 divided by 4, which is 0. Therefore, the last digit of 333 to the power of 444 is the same as the last digit of 3 to the power of 4, which is 1.
It is 1.
Well, isn't that a happy little math problem! When we look at the unit digit of powers of numbers, we focus on the cyclical pattern they follow. The unit digit of 3 raised to any power follows a pattern: 3, 9, 7, 1, and then repeats. So, to find the unit digit of 3 to the power of 34 factorial, we look for the remainder when 34 factorial is divided by 4, which is 2. Therefore, the unit digit of 3 to the power of 34 factorial is 9.
this is a guess and check problem. answers is 1009. 999 - 10 = 989 lets try one less (998) 998 -9(1 digit) is not possible, lets try one more (1000) 1000(4 digit) - 11 is not possible so only possible solution is (999,10) Answers is 999+10 = 1009
To find the last digit of 373^333, we need to look for a pattern in the units digit of the powers of 3. The units digit of powers of 3 cycles every 4 powers: 3^1 = 3, 3^2 = 9, 3^3 = 7, 3^4 = 1, and then it repeats. Since 333 is one less than a multiple of 4, the units digit of 3^333 will be the third number in the cycle, which is 7. Therefore, the last digit of 373^333 is 7.
No.
1, 3, 9, 1009, 3027, 9081 3 and 1009 are prime.
1155
3
3
it is 3