2, 3, 5, And 7 are the first 4 prime numbers
1, 3, 9, 1009, 3027, 9081 3 and 1009 are prime.
No.
1155
it is 3
The number that comes before 1010 is 1009. In the decimal number system, each digit represents a power of 10, with the rightmost digit representing 10^0 (1), the next digit representing 10^1 (10), and so on. Therefore, to find the number before 1010, you simply subtract 1 from the last digit, resulting in 1009.
2, 3, 5, And 7 are the first 4 prime numbers
Oh, what a happy little question! Let's paint a picture with numbers. When we raise 3 to any power, the last digit of the result follows a pattern: 3, 9, 7, 1, and then repeats. Since 444 is divisible by 4, the last digit of 3 to the power of 444 is 1. Let's add a touch of joy and say that the answer is a beautiful, calming 1.
It is 1.
The last digit is 3. If you multiply 3 repeatedly by itself, you get the last digits:3, 9, 7, 1, 3, 9, 7, 1... In other words, every fourth power of 3 will end with the digit 1. Since any factorial starting at 4! has 4 as a factor, it follows that the last digit is 1.
this is a guess and check problem. answers is 1009. 999 - 10 = 989 lets try one less (998) 998 -9(1 digit) is not possible, lets try one more (1000) 1000(4 digit) - 11 is not possible so only possible solution is (999,10) Answers is 999+10 = 1009
answer is 3 sol: always divide power by 4 so here 333/4=83 and remainder is 1 then we take unit digit of the number which is 373 unit digit is 3 now 3^1 is 3 so units digit of 373^333 is 3
1, 3, 9, 1009, 3027, 9081 3 and 1009 are prime.
No.
1155
it is 3
3