I think the last digit would be 5
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The last digit of a number raised to a power can be determined by finding a pattern in the units digits of the number's powers. For 2 raised to the power of 1997, the units digit will follow a pattern of 2, 4, 8, 6. Since 1997 is one less than a multiple of 4, the last digit will be 8.
the unit digit is the last digit from left or ones digit
i can tel one digit ie... 1 tens digit i dont knoww sorry will tel u later
The last digit is 4.
I think the last digit would be 5
To find the last digit of a number raised to a power, we can use the concept of modular arithmetic. The last digit of 333 to the power of 444 can be determined by finding the remainder when 333 is divided by 10, which is 3. Since the last digit of 333 is 3, we need to find the remainder of 444 divided by 4, which is 0. Therefore, the last digit of 333 to the power of 444 is the same as the last digit of 3 to the power of 4, which is 1.
It is the last digit of 34= 81. Therefore it is 1.It is the last digit of 34= 81. Therefore it is 1.It is the last digit of 34= 81. Therefore it is 1.It is the last digit of 34= 81. Therefore it is 1.
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1 :)
4.
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2 (The answer is 35184372088832)
The units' digit of 222 to the power 666 is 4.
The last digit: the 6.The last digit: the 6.The last digit: the 6.The last digit: the 6.
If the last digit is 0, 2, 4, 6, or 8, then the number is even. Otherwise it is odd.