810: quotient 1, remainder 1
To determine the least number to be subtracted from 789 to make it divisible by 56, first, calculate the remainder when 789 is divided by 56. Performing the division, 789 ÷ 56 gives a quotient of 14 and a remainder of 5. To make 789 divisible by 56, subtract this remainder from 56, which is 56 - 5 = 51. Therefore, the least number to be subtracted from 789 is 51.
1005
To solve this division problem, we need to find the number that, when divided into 40, gives a quotient of 6 with a remainder of 16. The formula to represent this situation is 40 = x * 6 + 16, where x is the number we are looking for. By rearranging the formula, we get x = (40 - 16) / 6, which simplifies to x = 24 / 6, and finally x = 4. Therefore, the number that, when divided into 40, gives a quotient of 6 with a remainder of 16 is 4.
How about 14 because 14/9 = 1 with a remainder of 5
It is 38.
75 ends (least significant digit) in 5 which is an odd number, hence the entire number 75 is odd. Also if you divide 75 by 2 you get a quotient of 37 and a remainder of 1. When a number is divided by 2 and you do not get a remainder of 0, the number is odd, otherwise it is even.
127 is the least prime number greater than 25 that will have a remainder of 2 when divided by 25.
To determine the least number to be subtracted from 789 to make it divisible by 56, first, calculate the remainder when 789 is divided by 56. Performing the division, 789 ÷ 56 gives a quotient of 14 and a remainder of 5. To make 789 divisible by 56, subtract this remainder from 56, which is 56 - 5 = 51. Therefore, the least number to be subtracted from 789 is 51.
1005
what least number must be subtracted from 13081 to get a number exactly divisible by 87
To solve this division problem, we need to find the number that, when divided into 40, gives a quotient of 6 with a remainder of 16. The formula to represent this situation is 40 = x * 6 + 16, where x is the number we are looking for. By rearranging the formula, we get x = (40 - 16) / 6, which simplifies to x = 24 / 6, and finally x = 4. Therefore, the number that, when divided into 40, gives a quotient of 6 with a remainder of 16 is 4.
How about 14 because 14/9 = 1 with a remainder of 5
9400÷65 gives144 quotient,40 remainder. 65×145 =9425 25 is the least
It is 38.
124/3 = 41 quotient, remainder 1 Increase quotient 42*3 = 126. difference of 126 and 124 is 2 . So 2 is to be added it is least.
The smallest number which can be divided by both 4 and 5 without a remainder is 20. This is also known as the Least Common Multiple (LCM).
10056÷23 gives 437 as quotient and 5 as remainder. Dividend-remainder= divisor× quotient so 10056-5=23×437 gives 10051.our question is least no should be added to 10056 which is divisible by 23. Check next possibility 23×438 gives 10074. Now 10056+18= 10074. Therefore 18 is the least number should be added to 10056 to get a number divisible by 23