810: quotient 1, remainder 1
1005
How about 14 because 14/9 = 1 with a remainder of 5
To solve this division problem, we need to find the number that, when divided into 40, gives a quotient of 6 with a remainder of 16. The formula to represent this situation is 40 = x * 6 + 16, where x is the number we are looking for. By rearranging the formula, we get x = (40 - 16) / 6, which simplifies to x = 24 / 6, and finally x = 4. Therefore, the number that, when divided into 40, gives a quotient of 6 with a remainder of 16 is 4.
It is 38.
832/48 gives 17 as quotient and 16 as remainder. Dividend-remainder=divisor*quotient 832-16 = 48*17 which is 816 that is divisible by 48. So 16 to be subracted.
75 ends (least significant digit) in 5 which is an odd number, hence the entire number 75 is odd. Also if you divide 75 by 2 you get a quotient of 37 and a remainder of 1. When a number is divided by 2 and you do not get a remainder of 0, the number is odd, otherwise it is even.
127 is the least prime number greater than 25 that will have a remainder of 2 when divided by 25.
1005
what least number must be subtracted from 13081 to get a number exactly divisible by 87
How about 14 because 14/9 = 1 with a remainder of 5
To solve this division problem, we need to find the number that, when divided into 40, gives a quotient of 6 with a remainder of 16. The formula to represent this situation is 40 = x * 6 + 16, where x is the number we are looking for. By rearranging the formula, we get x = (40 - 16) / 6, which simplifies to x = 24 / 6, and finally x = 4. Therefore, the number that, when divided into 40, gives a quotient of 6 with a remainder of 16 is 4.
9400÷65 gives144 quotient,40 remainder. 65×145 =9425 25 is the least
It is 38.
The smallest number which can be divided by both 4 and 5 without a remainder is 20. This is also known as the Least Common Multiple (LCM).
It is 1.1 = 0*12152128 r 1
25
124/3 = 41 quotient, remainder 1 Increase quotient 42*3 = 126. difference of 126 and 124 is 2 . So 2 is to be added it is least.