How about 14 because 14/9 = 1 with a remainder of 5
810: quotient 1, remainder 1
1005
It is 38.
121
To find the least number to be subtracted from 86295031 so that the remainder is divisible by 582, we first determine the remainder of 86295031 when divided by 582. Calculating (86295031 \mod 582) gives a remainder of 505. Therefore, to make the number exactly divisible by 582, we need to subtract this remainder, resulting in (505). Thus, the least number to subtract is 505.
127 is the least prime number greater than 25 that will have a remainder of 2 when divided by 25.
810: quotient 1, remainder 1
1005
501
True.Composite numbers are positive whole numbers that can be divided with no remainder by something other than 1 and themselves.Even numbers can be divided without remainder by 2, so any even number greater than 2 can be divided without remainder by at least three numbers: 1, 2, and the number itself. That makes the number composite.
It is 38.
The smallest number which can be divided by both 4 and 5 without a remainder is 20. This is also known as the Least Common Multiple (LCM).
It is 1.1 = 0*12152128 r 1
25
121
To find the least number to be subtracted from 86295031 so that the remainder is divisible by 582, we first determine the remainder of 86295031 when divided by 582. Calculating (86295031 \mod 582) gives a remainder of 505. Therefore, to make the number exactly divisible by 582, we need to subtract this remainder, resulting in (505). Thus, the least number to subtract is 505.
301