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log2 200 = ln 200 ÷ ln 2 = 7.6... → need 8 bits. If a signed number is being stored, then 9 bits would be needed as one would be needed to indicate the sign of the number.
5
110 = 00012 110 - This is the number one writen in the decimal system 00012 - This is the number 1 using the binary system. Here, 4 bits are being represented. 00012 = 012
28-bits
As quoted from Google Books, "Word size refers to the number of bits that a microprocessor can manipulate at one time."