To express the number 3 in binary, we need to determine the smallest power of 2 that can represent it. The binary representation of 3 is "11," which requires 2 bits (as 2^1 = 2 and 2^0 = 1, combining them gives 2 + 1 = 3). Therefore, the least number of bits needed to express 3 is 2.
log2 200 = ln 200 ÷ ln 2 = 7.6... → need 8 bits. If a signed number is being stored, then 9 bits would be needed as one would be needed to indicate the sign of the number.
5
To represent an eight-digit decimal number in Binary-Coded Decimal (BCD), each decimal digit is encoded using 4 bits. Since there are 8 digits in the number, the total number of bits required is 8 digits × 4 bits/digit = 32 bits. Therefore, 32 bits are needed to represent an eight-digit decimal number in BCD.
110 = 00012 110 - This is the number one writen in the decimal system 00012 - This is the number 1 using the binary system. Here, 4 bits are being represented. 00012 = 012
The number of digits in a binary number, also known as its bits, depends on its value. For a binary number representing a non-negative integer ( n ), the number of bits required can be calculated using the formula ( \lfloor \log_2(n) \rfloor + 1 ). For example, the binary representation of the decimal number 5 is ( 101 ), which has 3 bits. The number of bits increases as the value of ( n ) increases.
Four bits are required to write '12' as a binary number.(12)10 = ( 1 1 0 0 )2
11 bits. 211 = 2048
log2 200 = ln 200 ÷ ln 2 = 7.6... → need 8 bits. If a signed number is being stored, then 9 bits would be needed as one would be needed to indicate the sign of the number.
5
You would need at least 9 bits to borrow. Since 8 bits gives only 255 the additional bit will get you 256. Adding 256 + 128 gives you at least 384 subnets or hosts.
There are a number of different depths for a number of different bits. The depth needed depends on the project.
24 bits are needed for the program counter. Assuming the instructions are 32 bits, then 32 bits are needed for the instruction register.
18 in binary is 10010 Since 18 can't be written in term of 2 to the power x, the number of bits needed is 5. The answer is 5
45 in binary is 101101, so you need at least 6 bits to represent 45 characters.
To represent an eight-digit decimal number in Binary-Coded Decimal (BCD), each decimal digit is encoded using 4 bits. Since there are 8 digits in the number, the total number of bits required is 8 digits × 4 bits/digit = 32 bits. Therefore, 32 bits are needed to represent an eight-digit decimal number in BCD.
BY USING FORMULA (M+R+1)<=2r 011110110011001110101 ---- The formula d + p + 1 <= 2^p (where d is the number of data bits and p is the number of check bits) indicates that we need at least 5 check bits in order to correct single-bit errors in blocks of 16 data bits -- a (21,16) code. SECDED requires 6 check bits for blocks of 16 data bits.
Packing a lot of meaning into a small space