121
810: quotient 1, remainder 1
1005
How about 14 because 14/9 = 1 with a remainder of 5
It is 38.
To find the least number to be subtracted from 86295031 so that the remainder is divisible by 582, we first determine the remainder of 86295031 when divided by 582. Calculating (86295031 \mod 582) gives a remainder of 505. Therefore, to make the number exactly divisible by 582, we need to subtract this remainder, resulting in (505). Thus, the least number to subtract is 505.
127 is the least prime number greater than 25 that will have a remainder of 2 when divided by 25.
810: quotient 1, remainder 1
1005
How about 14 because 14/9 = 1 with a remainder of 5
It is 38.
The smallest number which can be divided by both 4 and 5 without a remainder is 20. This is also known as the Least Common Multiple (LCM).
25
It is 1.1 = 0*12152128 r 1
To find the least number to be subtracted from 86295031 so that the remainder is divisible by 582, we first determine the remainder of 86295031 when divided by 582. Calculating (86295031 \mod 582) gives a remainder of 505. Therefore, to make the number exactly divisible by 582, we need to subtract this remainder, resulting in (505). Thus, the least number to subtract is 505.
301
LCM of 45 & 50 = 450 so how about 456?
To find the least number that must be added to 37969 to make it exactly divisible by 65, first, we calculate the remainder when 37969 is divided by 65. The remainder is 44 (since 37969 ÷ 65 = 584 with a remainder of 44). To make it divisible by 65, we need to add (65 - 44 = 21). Thus, the least number that must be added is 21.