20 x 20
They will be both the same because the perimeter of the square is 32 units and the perimeter of the rectangle is also 32 units
Width = 3 Length = 34
The length is 20 units and the width is 10 units
length = 2 x width Perimeter = 2 x (length x width) =2 x (2 x width + width) = 2 x (3 x width) = 6 x width → 6 x width = 48 units → width = 48 units ÷ 6 = 8 units → length = 2 x width = 2 x 8 units = 16 units Ares = length x width = 16 units x 8 units = 128 square units
Area = Legth x Width In a square, Length = Width Therefore Area = Length x Length (or Width x Width) Area = Length squared Length = Square Root of 800 Perimeter = 4 x length Perimeter = 4 x Square Root of 800 Perimeter = 113.14
If the width is s units of length, then the perimeter is 4*s units.
They will be both the same because the perimeter of the square is 32 units and the perimeter of the rectangle is also 32 units
The perimeter of a rectangle having 1,000 units of width and 2,000 units of length is 6,000 units
Width = 3 Length = 34
The length is 20 units and the width is 10 units
length = 2 x width Perimeter = 2 x (length x width) =2 x (2 x width + width) = 2 x (3 x width) = 6 x width → 6 x width = 48 units → width = 48 units ÷ 6 = 8 units → length = 2 x width = 2 x 8 units = 16 units Ares = length x width = 16 units x 8 units = 128 square units
Area = Legth x Width In a square, Length = Width Therefore Area = Length x Length (or Width x Width) Area = Length squared Length = Square Root of 800 Perimeter = 4 x length Perimeter = 4 x Square Root of 800 Perimeter = 113.14
The perimeter is the sum of its 4 sides and its area is length times width
This is a rectangle with length 5 units and width 3 units. The area = length x width = 5 x 3 = 15 sq units. The perimeter = 2 x (length + width) = 2 x 8 = 16 units.
To draw a rectangle with an area of 35 square units and a perimeter of 35 units, you can use the formulas for area (A = length × width) and perimeter (P = 2(length + width)). Let the length be ( l ) and width be ( w ). From the area, you get ( lw = 35 ), and from the perimeter, ( 2(l + w) = 35 ) or ( l + w = 17.5 ). Solving these equations simultaneously, you can find suitable dimensions, such as ( l = 10 ) units and ( w = 3.5 ) units or ( l = 7 ) units and ( w = 5 ) units.
Draw the table and calculate the area of the triangle the area of a square is 36
It could be rectangle that has a length of 6 units and a width of 2 units.