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What is the width of a rectangular if the area is 40.64 sq ft length is 12.7 ft?
Length*Width = Area so Width = Area/Length = 40.64 sq ft/12.7 ft = 3.2 ft.
What is the width of a rectangle with a perimeter of 70 feet if its length is 1 feet 2 feet?
Perimeter = 2(length + width) → width = perimeter ÷ 2 - length length = 1 foot → width = 70 ft ÷ 2 - 1 ft = 34 ft; length = 2 feet → width = 70 ft ÷ 2 - 2 ft = 33 ft.
If a room as an area of 925 square feet what is the width if the length is 37 feet?
area = width x length width = area/length width = 925 sq ft/37 ft width = 25 ft
What is the width of a rectangular floor that has an area of 255 sq ft and a length of 17 ft?
Area = Length*Width so Width = Area/Length = 255/17 ft = 15 feet.
The perimeter of a standard- sized rectangular rug is 94 ft the length is 3 ft more than the width Find the length and the width?
The perimeter of a standard- sized rectangular rug is 94 ft. the length is 3 ft more than the width. Find the length and the width.
How big is Jennette mccurdy house?
7,257 width in ft 8,542 length in ft
What is the surface area of the roman Colosseum?
The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.
What is the width of a rectangular if the area is 40.64 sq ft length is 12.7 ft?
Length*Width = Area so Width = Area/Length = 40.64 sq ft/12.7 ft = 3.2 ft.
What is the width of a rectangle with a perimeter of 70 feet if its length is 1 feet 2 feet?
Perimeter = 2(length + width) → width = perimeter ÷ 2 - length length = 1 foot → width = 70 ft ÷ 2 - 1 ft = 34 ft; length = 2 feet → width = 70 ft ÷ 2 - 2 ft = 33 ft.
If a room as an area of 925 square feet what is the width if the length is 37 feet?
area = width x length width = area/length width = 925 sq ft/37 ft width = 25 ft
what- a rectangular house has a perimeter of 140 feet. The length of the house is 50 feet.What is the width of the house in feet?
20 ft.
If a rectangular house is 44 square yards and the length is 36 feet what is the width of the house?
44 sq yd = 396 sq ft, so width = 396/36 = 11 ft
What is the width of a rectangular floor that has an area of 255 sq ft and a length of 17 ft?
Area = Length*Width so Width = Area/Length = 255/17 ft = 15 feet.
What is the length of runway at lax airport?
Runway: 25R Length x Width: 12923 ft x 150 ft Runway: 07L Length x Width: 12923 ft x 150 ft Runway: 25L Length x Width: 11095 ft x 200 ft Runway: 24R Length x Width: 8926 ft x 150 ft Runway: 24L Length x Width: 10885 ft x 150 ft Runway: 07R Length x Width: 11095 ft x 200 ft Runway: 06R Length x Width: 10885 ft x 150 ft Runway: 06L Los Angeles Ramp/Taxi: 131.45
The perimeter of a standard- sized rectangular rug is 94 ft the length is 3 ft more than the width Find the length and the width?
The perimeter of a standard- sized rectangular rug is 94 ft. the length is 3 ft more than the width. Find the length and the width.
What is the relationship betwee length 40 ft width 20 ft?
From here, it appears that the length is double the width.
The width of a rectangle is 2ft less than the length The area is 8 ft squared Find the length and the width?
Easy. Width = 2ft, Length = 4 ft, therefore the Area = 8 ft.
