Assuming that length is the larger of the two, it could be anything larger than 137.84 ft. [137.84 = sqrt(19000)]
eg 190 ft * 100 ft
or 1900 ft * 10 ft
or 19000 ft * 1ft
or 190000 ft * 0.1 ft
the list is endless.
Then, you could have 380 ft * 50 ft
or 3800 ft * 5 ft
etc, etc.
Length*Width = Area so Width = Area/Length = 40.64 sq ft/12.7 ft = 3.2 ft.
Perimeter = 2(length + width) → width = perimeter ÷ 2 - length length = 1 foot → width = 70 ft ÷ 2 - 1 ft = 34 ft; length = 2 feet → width = 70 ft ÷ 2 - 2 ft = 33 ft.
area = width x length width = area/length width = 925 sq ft/37 ft width = 25 ft
Area = Length*Width so Width = Area/Length = 255/17 ft = 15 feet.
The perimeter of a standard- sized rectangular rug is 94 ft. the length is 3 ft more than the width. Find the length and the width.
The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.
Length*Width = Area so Width = Area/Length = 40.64 sq ft/12.7 ft = 3.2 ft.
Perimeter = 2(length + width) → width = perimeter ÷ 2 - length length = 1 foot → width = 70 ft ÷ 2 - 1 ft = 34 ft; length = 2 feet → width = 70 ft ÷ 2 - 2 ft = 33 ft.
area = width x length width = area/length width = 925 sq ft/37 ft width = 25 ft
To find the width of a rectangular lot, you can use the formula for area: Area = Length × Width. Given that the area is 4000 square feet and the length is 50 feet, you can rearrange the formula to solve for width: Width = Area / Length. Plugging in the values, Width = 4000 sq ft / 50 ft, which equals 80 feet. Thus, the width of the lot is 80 feet.
Area = Length*Width so Width = Area/Length = 255/17 ft = 15 feet.
Runway: 25R Length x Width: 12923 ft x 150 ft Runway: 07L Length x Width: 12923 ft x 150 ft Runway: 25L Length x Width: 11095 ft x 200 ft Runway: 24R Length x Width: 8926 ft x 150 ft Runway: 24L Length x Width: 10885 ft x 150 ft Runway: 07R Length x Width: 11095 ft x 200 ft Runway: 06R Length x Width: 10885 ft x 150 ft Runway: 06L Los Angeles Ramp/Taxi: 131.45
The perimeter of a standard- sized rectangular rug is 94 ft. the length is 3 ft more than the width. Find the length and the width.
From here, it appears that the length is double the width.
1 acre = 43560 sq ft→ 0.18 acre = 0.18 x 43560 sq ft= 7840.8 sq ft.There is no definite answer for the length and width of a building lot as the building lot can have any length and width as long asits area(length x width) is 7840.8 sq ft.If it is a square building lot, it would be approx 88.55 ft by 88.55 ft.However, if it is rectangular, it could be approx 98 ft by 80 ft, or 131 ft by 60 ft, or 196 ft by 40 ft, or 157 ft by 50 ft, or even 7480 ft by 1 ft!
Easy. Width = 2ft, Length = 4 ft, therefore the Area = 8 ft.
The area formula is: Area = length x width Let: length = 40 ft width = 50 ft Then: A = 40 ft x 50 ft = 2000 ft²