18cm is the area and perimeter. the width is 3cm.
length=18cm width=10cm (you use a system of equations: 2L+2W=56, L=2W-2)
Width of rectangle: 144/18 = 8cm Perimeter of rectangle: 2*(18+8) = 52cm
Perimeter = 2 x L + W so L + W = 9, this would be 6 x 3 to give area of 18
The dimensions of the rectangle are 5 cm by 4 cm
The length of the rectangle is 18cm. The width of the rectangle is 9cm.
18cm is the area and perimeter. the width is 3cm.
450 square centimeters
length=18cm width=10cm (you use a system of equations: 2L+2W=56, L=2W-2)
Width of rectangle: 144/18 = 8cm Perimeter of rectangle: 2*(18+8) = 52cm
An arbitrary large number is the answer for anyrectangle, up to that with a length of 9cm, and 0cm as the width will have a perimeter of 18cm.Similarly, any rectangle up to that with sides 0cm long, and a width of 9cm will have your 18cm perimeter.
Perimeter = 2 x L + W so L + W = 9, this would be 6 x 3 to give area of 18
1:1.23
The dimensions of the rectangle are 5 cm by 4 cm
Well, isn't that just a happy little rectangle! To find the perimeter, you simply add up all the sides. So for this rectangle with sides of 24cm and 18cm, you would add 24 + 24 + 18 + 18 to get a perimeter of 84cm. Just imagine that perimeter as a lovely border framing your beautiful rectangle painting!
Area = 6*18 = 108 square cm
It is impossible to say. Let L be ANY number such that 4.5 ≤ L < 9 cm and let B = (9 - L) cm. Then for every one of the infinite number of values of L, there will be a different rectangle whose perimeter will be 18 cm.