The length and width of a rectangle with an area of 18 cm² can vary, as multiple dimensions can produce the same area. For example, one possible pair of dimensions is 6 cm for the length and 3 cm for the width, since 6 cm × 3 cm = 18 cm². Other combinations, such as 9 cm by 2 cm or 1 cm by 18 cm, would also yield the same area.
18cm is the area and perimeter. the width is 3cm.
Width of rectangle: 144/18 = 8cm Perimeter of rectangle: 2*(18+8) = 52cm
length=18cm width=10cm (you use a system of equations: 2L+2W=56, L=2W-2)
Perimeter = 2 x L + W so L + W = 9, this would be 6 x 3 to give area of 18
Well, isn't that just a happy little rectangle! To find the perimeter, you simply add up all the sides. So for this rectangle with sides of 24cm and 18cm, you would add 24 + 24 + 18 + 18 to get a perimeter of 84cm. Just imagine that perimeter as a lovely border framing your beautiful rectangle painting!
The length of the rectangle is 18cm. The width of the rectangle is 9cm.
18cm is the area and perimeter. the width is 3cm.
450 square centimeters
Width of rectangle: 144/18 = 8cm Perimeter of rectangle: 2*(18+8) = 52cm
length=18cm width=10cm (you use a system of equations: 2L+2W=56, L=2W-2)
An arbitrary large number is the answer for anyrectangle, up to that with a length of 9cm, and 0cm as the width will have a perimeter of 18cm.Similarly, any rectangle up to that with sides 0cm long, and a width of 9cm will have your 18cm perimeter.
Perimeter = 2 x L + W so L + W = 9, this would be 6 x 3 to give area of 18
1:1.23
Well, isn't that just a happy little rectangle! To find the perimeter, you simply add up all the sides. So for this rectangle with sides of 24cm and 18cm, you would add 24 + 24 + 18 + 18 to get a perimeter of 84cm. Just imagine that perimeter as a lovely border framing your beautiful rectangle painting!
The dimensions of the rectangle are 5 cm by 4 cm
Area = 6*18 = 108 square cm
It is impossible to say. Let L be ANY number such that 4.5 ≤ L < 9 cm and let B = (9 - L) cm. Then for every one of the infinite number of values of L, there will be a different rectangle whose perimeter will be 18 cm.