Perimeter = 2 x L + W so L + W = 9, this would be 6 x 3 to give area of 18
18cm is the area and perimeter. the width is 3cm.
length=18cm width=10cm (you use a system of equations: 2L+2W=56, L=2W-2)
Width of rectangle: 144/18 = 8cm Perimeter of rectangle: 2*(18+8) = 52cm
It is: 162/9 = 18cm
Well, isn't that just a happy little rectangle! To find the perimeter, you simply add up all the sides. So for this rectangle with sides of 24cm and 18cm, you would add 24 + 24 + 18 + 18 to get a perimeter of 84cm. Just imagine that perimeter as a lovely border framing your beautiful rectangle painting!
18cm is the area and perimeter. the width is 3cm.
The length of the rectangle is 18cm. The width of the rectangle is 9cm.
An arbitrary large number is the answer for anyrectangle, up to that with a length of 9cm, and 0cm as the width will have a perimeter of 18cm.Similarly, any rectangle up to that with sides 0cm long, and a width of 9cm will have your 18cm perimeter.
length=18cm width=10cm (you use a system of equations: 2L+2W=56, L=2W-2)
Width of rectangle: 144/18 = 8cm Perimeter of rectangle: 2*(18+8) = 52cm
1:1.23
It is: 162/9 = 18cm
Well, isn't that just a happy little rectangle! To find the perimeter, you simply add up all the sides. So for this rectangle with sides of 24cm and 18cm, you would add 24 + 24 + 18 + 18 to get a perimeter of 84cm. Just imagine that perimeter as a lovely border framing your beautiful rectangle painting!
450 square centimeters
The dimensions of the rectangle are 5 cm by 4 cm
It is impossible to say. Let L be ANY number such that 4.5 ≤ L < 9 cm and let B = (9 - L) cm. Then for every one of the infinite number of values of L, there will be a different rectangle whose perimeter will be 18 cm.
You need the length and/or width: could be 1 x 18, 2 x 9, 3 x 6 etc which would have perimeters of 38 cm, 22 cm and 18 cm respectively. Perimeter = 2 x (L + W)