1.08 metres.
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Suppose the width is w cm Then length is 2w + 6 cm So, the perimeter is 2l + 2w = 2*(2w + 6) + 2w = 4w + 12 + 2w = 6w + 12 Thus 6w + 12 = 108 so that 6w = 96 and then w = 16 cm And then, l = 2w + 6 = 32 + 6 = 38 cm
30 cm.
The edge length of a regular hexagon with a perimeter of 24 cm is 24/6 = 4 cm
The perimeter is two times the sum of the width and length expressed in cm. The area is the length times the width expressed in square cm.
The answer depends on what information you do have: the length of a side, or a diagonal, the area, ... If a side is of length s cm then the perimeter is 4*s cm.