Suppose the width is w cm Then length is 2w + 6 cm So, the perimeter is 2l + 2w = 2*(2w + 6) + 2w = 4w + 12 + 2w = 6w + 12 Thus 6w + 12 = 108 so that 6w = 96 and then w = 16 cm And then, l = 2w + 6 = 32 + 6 = 38 cm
30 cm.
The edge length of a regular hexagon with a perimeter of 24 cm is 24/6 = 4 cm
The perimeter is two times the sum of the width and length expressed in cm. The area is the length times the width expressed in square cm.
The answer depends on what information you do have: the length of a side, or a diagonal, the area, ... If a side is of length s cm then the perimeter is 4*s cm.
umm 108cm?
Suppose the width is w cm Then length is 2w + 6 cm So, the perimeter is 2l + 2w = 2*(2w + 6) + 2w = 4w + 12 + 2w = 6w + 12 Thus 6w + 12 = 108 so that 6w = 96 and then w = 16 cm And then, l = 2w + 6 = 32 + 6 = 38 cm
30 cm.
If a triangle with a perimeter of 24 cm is an equilateral triangle, then each of its 3 sides will be 8 cm in length
The edge length of a regular hexagon with a perimeter of 24 cm is 24/6 = 4 cm
If a polygon with a perimeter of 30 centimeters has sides with length 6 cm/side, then it has 30 cm / 6 cm per side = 5 sides. So a regular pentagon with a side length of 6 cm has a perimeter of 30 centimeters.
The length could be 3 cm (width = 1 cm), with a perimeter of 8 cm, which is not more than 72 cm. Or it could be 6 cm (w = 2 cm, perimeter = 16 cm).
20 cm
The perimeter is two times the sum of the width and length expressed in cm. The area is the length times the width expressed in square cm.
The answer depends on what information you do have: the length of a side, or a diagonal, the area, ... If a side is of length s cm then the perimeter is 4*s cm.
Perimeter of Rectangle = 2(length + width) =2(45+30) =150 cm
perimeter = 2*width + 2*length 36= 2*8 +2*length2*length=36-162*length=20length = 10 cm