The perimeter is two times the sum of the width and length expressed in cm.
The area is the length times the width expressed in square cm.
To find the perimeter of a rectangle, you add up the lengths of all its sides. In this case, the rectangle has two sides of 14 cm and two sides of 32 cm. Therefore, the perimeter would be 14 + 14 + 32 + 32 = 92 cm. To find the area of a rectangle, you multiply the length by the width. In this case, the length is 32 cm and the width is 14 cm. Therefore, the area would be 32 x 14 = 448 square cm.
11 cm2 zero, when two opposite sides are 12 cm, and the rectangle is infinitely thin
Any number less than 576 cm2. A square, with sides of 24 cm will have a perimeter of 96 cm and an area of 576 cm2. Suppose the sides of the rectangle are 24+x cm and 24-x cm, where 0<x<24. Then the perimeter will be 96 cm while the area will be (24+x)*(24-x) = 576 - x2 cm2 The area can have any value in the range (0, 576) depending on the value of x.
Length = 254/2 ie 127 cm. Perimeter = twice (L + W) = 2 x (127 + 2) = 258 cm
Consider a square with sides of length x cm whose area is x2 cm and perimeter is 4x cm. Next consider a rectangle with sides of 2x cm and x/2 cm. It area is 2x*x/2 = x2, the same as for the square. But its perimeter is 2*(2x+x/2) = 5x > perimeter of the square. Perimeter of 3x * x/3 = 62/3x cm. Perimeter of 100x * x/100 = 200.02x cm Perimeter of 1000000x * x/1000000 = 2000000.000002x cm. As you can see, it is possible to increase the perimeter without limit.
A rectangle with sides of 1cm and 6cm has an area of 6 cm2 and a perimeter of 14 cm. A rectangle with sides of 2cm and 3cm has the same area but its perimeter is 10 cm.
To find the perimeter of a rectangle, you add up the lengths of all its sides. In this case, the rectangle has two sides of 14 cm and two sides of 32 cm. Therefore, the perimeter would be 14 + 14 + 32 + 32 = 92 cm. To find the area of a rectangle, you multiply the length by the width. In this case, the length is 32 cm and the width is 14 cm. Therefore, the area would be 32 x 14 = 448 square cm.
11 cm2 zero, when two opposite sides are 12 cm, and the rectangle is infinitely thin
To answer this simply try a few out for yourself. In a 2x1 cm rectangle, the area is 2 cm squared and the perimeter is 6 cm In a 12x10 rectangle, the area is 120 cm squared and the perimeter is 44 cm. In some cases, the perimeter is larger and in others it is smaller. To answer your question, no, the perimeter of a rectangle is NOT always greater than its area.
The greatest area that a rectangle can have is, in fact, attained when it is a square. A square with perimeter of 16 cm must have sides of 4 cm and so an area of 4*4 = 16 cm2.
Any number less than 576 cm2. A square, with sides of 24 cm will have a perimeter of 96 cm and an area of 576 cm2. Suppose the sides of the rectangle are 24+x cm and 24-x cm, where 0<x<24. Then the perimeter will be 96 cm while the area will be (24+x)*(24-x) = 576 - x2 cm2 The area can have any value in the range (0, 576) depending on the value of x.
Area: 54 square cm Perimeter: 30 cm
Length = 254/2 ie 127 cm. Perimeter = twice (L + W) = 2 x (127 + 2) = 258 cm
Perimeter of a rectangle is 2(l+b).Area of rectangle is 216 centimeter square.
The perimeter and area don't depend on each other. Knowing one doesn't tell you the other. -- A circle with perimeter (circumference) of 20 cm has area of 31.83 cm2. -- A square with perimeter of 20 cm has area of 25 cm2 . -- A (9 x 1) rectangle has perimeter of 20 cm and area of 9 cm2 . -- A (8 x 2) rectangle has perimeter of 20 cm and area of 16 cm2 . -- A (7 x 3) rectangle has perimeter of 20 cm and area of 21 cm2 . -- A (6 x 4) rectangle has perimeter of 20 cm and area of 24 cm2 .
Length + width = half of perimeter, ie 18 cm. 18 - 4 = 14, 14/2 = 7 so sides are 7 and 11 cm and area = 77sq cm
100 cm