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The pendulum's length is 0.36 meters or 1.18 feet.

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Q: What is the length of a pendulum with a period of 1.20 s?
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What is the length of a pendulum with a period of 1.49 s?

pendulum length (L)=1.8081061073513foot pendulum length (L)=0.55111074152067meter


A pendulum swings back and forth with a period of 0.5 s What is the length of the pendulum arm?

The pendulum has an arm length of 0.06 meters or 2.36 inches.


What is the length of a pendulum with a period of 4.48ses?

The length of a pendulum can be calculated using the formula L = (g * T^2) / (4 * Ļ€^2), where L is the length of the pendulum, g is the acceleration due to gravity (approximately 9.81 m/s^2), T is the period of the pendulum (4.48 s in this case), and Ļ€ is a mathematical constant. By substituting the values into the formula, the length of the pendulum with a period of 4.48 s can be determined.


What factor has the greatest effect on the period of a pendulum?

The length of the pendulum has the greatest effect on its period. A longer pendulum will have a longer period, while a shorter pendulum will have a shorter period. The mass of the pendulum bob and the angle of release also affect the period, but to a lesser extent.


What is the length of a pendulum that has a period of 0.7 s?

The length of a pendulum with a period of 0.7 seconds can be calculated using the formula T = 2Ļ€āˆš(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. Rearranging the formula gives L = (T^2 * g) / (4Ļ€^2). Substituting T = 0.7 s and g = 9.81 m/s^2, the length of the pendulum is approximately 0.46 meters.


What is the length in inches of a simple pendulum whose period s 1 s?

9.5 inches


A pendulum has a period on the earth of 1.35 s What is its period on the surface of the moon where g equals 1.62 meters per second squared?

The period of a pendulum is given by T = 2Ļ€āˆš(L/g), where L is the length of the pendulum and g is the acceleration due to gravity. Since the pendulum's length and mass do not change, its period on the moon would be T = 2Ļ€āˆš(L/1.62), assuming the pendulum is the same length. Solving for T gives 2.56 seconds.


What is the period of a 25 kg pendulum with a length of 45 m?

The period of a pendulum is given by T = 2Ļ€āˆš(L/g), where L is the length of the pendulum and g is the acceleration due to gravity (approximately 9.81 m/s^2). Plugging in the values, T = 2Ļ€āˆš(45/9.81) ā‰ˆ 9.0 s.


What time required in 1 oscillation of pendulum?

The time required for one complete oscillation (or swing) of a pendulum is known as its period. The period of a simple pendulum depends on its length and the acceleration due to gravity. The formula to calculate the period of a pendulum is T = 2Ļ€āˆš(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity (approximately 9.81 m/s^2).


What would be the period of a1.0 m length pendulum if it were oscillating on the moon?

The period of a pendulum is given by T = 2Ļ€āˆš(L/g), where L is the length of the pendulum and g is the acceleration due to gravity. On the moon, the acceleration due to gravity is approximately 1.625 m/s^2, so the period of a 1.0 m length pendulum would be T = 2Ļ€āˆš(1.0/1.625) ā‰ˆ 3.58 seconds.


The period of a pendulum of length 0.500 m is?

The period of a pendulum can be calculated using the formula T = 2Ļ€āˆš(L/g), where T is the period, L is the length of the pendulum (0.500 m in this case), and g is the acceleration due to gravity (approximately 9.81 m/s^2). Plugging in the values, the period of the pendulum with a length of 0.500 m can be calculated.


What pendulum length in Nairobi would have a time period of 1s?

Assuming a gravitational acceleration of 9.81 m/s^2, a pendulum in Nairobi with a length of approximately 0.25 meters would have a time period of around 1 second. This is calculated using the formula T = 2Ļ€āˆš(L/g), where T is the time period, L is the length of the pendulum, and g is the gravitational acceleration.