Q: What is the length of a pendulum with a period of 1.20 s?

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The pendulum has an arm length of 0.06 meters or 2.36 inches.

9.5 inches

To predict the period of a pendulum, we can use the equation T = 2Ļā(L/g), where T is the period, L is the length of the string, and g is the acceleration due to gravity. Plugging in L = 24cm (or 0.24m) and g = 9.8 m/sĀ², we can calculate the period using this equation.

Time period and length of a pendulum are related by: T = 2(pi)(L).5(g).5 so putting in the values and solving for g yields a result of : g = 9.70 ms-2

Pendulums have been used for thousands of years as a time keeping device in various civilizations. Assuming that it is only displaced by a small angle, a pendulum wall have a period of 2pi*√(L/g) where L is the length of the pendulum and g is the acceeleration due to gravity, normally 9.81m/s². One of the cool things about pendulums is that if one is made with a length of one meter, it will have a period of 2.00607 seconds, meaning it will take just slightly more than one second to swing from one side to another.

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pendulum length (L)=1.8081061073513foot pendulum length (L)=0.55111074152067meter

The pendulum has an arm length of 0.06 meters or 2.36 inches.

The length of a pendulum can be calculated using the formula L = (g * T^2) / (4 * Ļ^2), where L is the length of the pendulum, g is the acceleration due to gravity (approximately 9.81 m/s^2), T is the period of the pendulum (4.48 s in this case), and Ļ is a mathematical constant. By substituting the values into the formula, the length of the pendulum with a period of 4.48 s can be determined.

The length of the pendulum has the greatest effect on its period. A longer pendulum will have a longer period, while a shorter pendulum will have a shorter period. The mass of the pendulum bob and the angle of release also affect the period, but to a lesser extent.

The length of a pendulum with a period of 0.7 seconds can be calculated using the formula T = 2Ļā(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. Rearranging the formula gives L = (T^2 * g) / (4Ļ^2). Substituting T = 0.7 s and g = 9.81 m/s^2, the length of the pendulum is approximately 0.46 meters.

9.5 inches

The period of a pendulum is given by T = 2Ļā(L/g), where L is the length of the pendulum and g is the acceleration due to gravity. Since the pendulum's length and mass do not change, its period on the moon would be T = 2Ļā(L/1.62), assuming the pendulum is the same length. Solving for T gives 2.56 seconds.

The period of a pendulum is given by T = 2Ļā(L/g), where L is the length of the pendulum and g is the acceleration due to gravity (approximately 9.81 m/s^2). Plugging in the values, T = 2Ļā(45/9.81) ā 9.0 s.

The time required for one complete oscillation (or swing) of a pendulum is known as its period. The period of a simple pendulum depends on its length and the acceleration due to gravity. The formula to calculate the period of a pendulum is T = 2Ļā(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity (approximately 9.81 m/s^2).

The period of a pendulum is given by T = 2Ļā(L/g), where L is the length of the pendulum and g is the acceleration due to gravity. On the moon, the acceleration due to gravity is approximately 1.625 m/s^2, so the period of a 1.0 m length pendulum would be T = 2Ļā(1.0/1.625) ā 3.58 seconds.

The period of a pendulum can be calculated using the formula T = 2Ļā(L/g), where T is the period, L is the length of the pendulum (0.500 m in this case), and g is the acceleration due to gravity (approximately 9.81 m/s^2). Plugging in the values, the period of the pendulum with a length of 0.500 m can be calculated.

Assuming a gravitational acceleration of 9.81 m/s^2, a pendulum in Nairobi with a length of approximately 0.25 meters would have a time period of around 1 second. This is calculated using the formula T = 2Ļā(L/g), where T is the time period, L is the length of the pendulum, and g is the gravitational acceleration.