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A pendulum swings back and forth with a period of 0.5 s What is the length of the pendulum arm?
The pendulum has an arm length of 0.06 meters or 2.36 inches.
What is the length in inches of a simple pendulum whose period s 1 s?
9.5 inches
How do you predict the period of the pendulum if the length of string was 24cm?
The period of a pendulum (for very small swings) can be estimated as ...T = 2 pi (L/G)0.5... so, plugging in 0.024 m for L, and 9.81 m s-2 for G, we get L = 0.31 seconds.
What is the free-fall acceleration in a location where the period of a 0.850 m long pendulum is 1.86 s?
Time period and length of a pendulum are related by: T = 2(pi)(L).5(g).5 so putting in the values and solving for g yields a result of : g = 9.70 ms-2
What is the purpose of a pendulum?
Pendulums have been used for thousands of years as a time keeping device in various civilizations. Assuming that it is only displaced by a small angle, a pendulum wall have a period of 2pi*√(L/g) where L is the length of the pendulum and g is the acceeleration due to gravity, normally 9.81m/s². One of the cool things about pendulums is that if one is made with a length of one meter, it will have a period of 2.00607 seconds, meaning it will take just slightly more than one second to swing from one side to another.
What is the length of a pendulum with a period of 1.49 s?
pendulum length (L)=1.8081061073513foot pendulum length (L)=0.55111074152067meter
A pendulum swings back and forth with a period of 0.5 s What is the length of the pendulum arm?
The pendulum has an arm length of 0.06 meters or 2.36 inches.
What is the length of a pendulum with a period of 4.48ses?
The length of a pendulum can be calculated using the formula L = (g * T^2) / (4 * π^2), where L is the length of the pendulum, g is the acceleration due to gravity (approximately 9.81 m/s^2), T is the period of the pendulum (4.48 s in this case), and π is a mathematical constant. By substituting the values into the formula, the length of the pendulum with a period of 4.48 s can be determined.
What factor has the greatest effect on the period of a pendulum?
The length of the pendulum has the greatest effect on its period. A longer pendulum will have a longer period, while a shorter pendulum will have a shorter period. The mass of the pendulum bob and the angle of release also affect the period, but to a lesser extent.
What is the length of a pendulum that has a period of 0.7 s?
The length of a pendulum with a period of 0.7 seconds can be calculated using the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. Rearranging the formula gives L = (T^2 * g) / (4π^2). Substituting T = 0.7 s and g = 9.81 m/s^2, the length of the pendulum is approximately 0.46 meters.
What is the length in inches of a simple pendulum whose period s 1 s?
9.5 inches
A pendulum has a period on the earth of 1.35 s What is its period on the surface of the moon where g equals 1.62 meters per second squared?
The period of a pendulum is given by T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity. Since the pendulum's length and mass do not change, its period on the moon would be T = 2π√(L/1.62), assuming the pendulum is the same length. Solving for T gives 2.56 seconds.
What is the period of a 25 kg pendulum with a length of 45 m?
The period of a pendulum is given by T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity (approximately 9.81 m/s^2). Plugging in the values, T = 2π√(45/9.81) ≈ 9.0 s.
What time required in 1 oscillation of pendulum?
The time required for one complete oscillation (or swing) of a pendulum is known as its period. The period of a simple pendulum depends on its length and the acceleration due to gravity. The formula to calculate the period of a pendulum is T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity (approximately 9.81 m/s^2).
What would be the period of a1.0 m length pendulum if it were oscillating on the moon?
The period of a pendulum is given by T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity. On the moon, the acceleration due to gravity is approximately 1.625 m/s^2, so the period of a 1.0 m length pendulum would be T = 2π√(1.0/1.625) ≈ 3.58 seconds.
The period of a pendulum of length 0.500 m is?
The period of a pendulum can be calculated using the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum (0.500 m in this case), and g is the acceleration due to gravity (approximately 9.81 m/s^2). Plugging in the values, the period of the pendulum with a length of 0.500 m can be calculated.
What pendulum length in Nairobi would have a time period of 1s?
Assuming a gravitational acceleration of 9.81 m/s^2, a pendulum in Nairobi with a length of approximately 0.25 meters would have a time period of around 1 second. This is calculated using the formula T = 2π√(L/g), where T is the time period, L is the length of the pendulum, and g is the gravitational acceleration.
