135.15 sq. cm
165.8 sq cm
The area of a trapezoid is 1/2 times the sum of the bases * the height. In this case, we have the area of 65 = 1/2 * (13+13) * height. Solving for height, we have 65 * 2 / 26, so h = 5. If the two bases of a quadrilateral are of the same length, it is not a parallelogram, but a rectangle.
6
To find the area of a trapezoid, you need the lengths of the two parallel sides (bases) and the height. However, the dimensions given (13 and 20) appear to specify the lengths of the bases without mentioning the height. If we assume the height is also provided or inferred, the area formula is ( \text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h ). Without the height, we cannot calculate the area definitively.
It is 20 units.
135.15 sq. cm
165.8 sq cm
The area of a trapezoid is 1/2 times the sum of the bases * the height. In this case, we have the area of 65 = 1/2 * (13+13) * height. Solving for height, we have 65 * 2 / 26, so h = 5. If the two bases of a quadrilateral are of the same length, it is not a parallelogram, but a rectangle.
6
To find the area of a trapezoid, you need the lengths of the two parallel sides (bases) and the height. However, the dimensions given (13 and 20) appear to specify the lengths of the bases without mentioning the height. If we assume the height is also provided or inferred, the area formula is ( \text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h ). Without the height, we cannot calculate the area definitively.
Using Pythagoras' theorem the length of the hypotenuse is 13 units
Isosceles trapezoid ABCD has an area of 276 If AD = 13 inches and DE = 12 inches, find AB.
8
Assuming the height is 13 inches (not 13 feet or something else), Area = 0.5*(12+14)*13 = 169 sq inches.
13 feet
It is the square root of 169 which is 13 units of length