Apply Pythagoras.
l^(2) + w^(2) = d^(2(
Substituting
16^(2) + 10^(2) = d^(2)
d^(2) = 256 + 100
d^(2) = 356
d = sqrt(356)
d = 18.86796226.... ft. = 23 ft 10.41,,, inches.,
Using Pythagoras' theorem its width is 6 units in length.
18.9 feet
A = 48 units2
The best way to do this would be to use the Pythagorean Theorem, but in reverse. So let's say the diagonal is 10, and the width is 8. You would do (10^2) / (8^2). This equals 36. The square root of 36 is 6. So your answer would be 6 for the length. Hope this answer helps!
The perimeter of a rectangle with length of 10 miles and width of 5 miles is 30 miles.
Diagonal = 10 meters.
Using Pythagoras' theorem its width is 6 units in length.
18.9 feet
The diagonal is 15.620 meters.
18.9 feet
Use Pythagoras: diagonal² = length² + width² → diagonal² = (10 cm)² + (15 cm)² → diagonal = √(10² + 15²) cm = √325 cm = 5 √13 cm ≈ 18 cm
A = 48 units2
The simplest Pythagorean triangle is 3, 4 and 5. Double this gives 6, 8 and 10 so the sides of your rectangle are 6 cm & 8 cm.
Width of rectangle: 50/10 = 5 cm
The best way to do this would be to use the Pythagorean Theorem, but in reverse. So let's say the diagonal is 10, and the width is 8. You would do (10^2) / (8^2). This equals 36. The square root of 36 is 6. So your answer would be 6 for the length. Hope this answer helps!
The perimeter of a rectangle with length of 10 miles and width of 5 miles is 30 miles.
The length of the rectangle is 10 cm, while the width is 3 cm. In a rectangle, the length is typically the longer side, and in this case, it is indeed longer than the width. Thus, the dimensions of the rectangle are 10 cm by 3 cm.