(0.5, 2)
Points: (2, 3) and (4, 7) Gradient or slope: change in y/change in x = (7-3)/(4-2) = 4/2 = 2
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As there is no change in y, the perpendicular bisector is given by x = (10 + k)/2 This is given as x = 7; thus: → (10 + k)/2 = 7 → 10 + k = 14 → k = 4
The midpoint of the line segment of (7, 2) and (2, 4) is at (4.5, 3)
Rain - 2011 Segment 7 2-4 was released on: USA: 17 May 2013
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The midpoint of the line segment from ( 3, 7 ) to ( 8, 2 ) is at ( 5.5, 4.5 )
(6, −4)
It is the square root of (-3-1)2+(-7--2)2 = 6.403 to three decimal places
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
If you mean points of (2, 4) and (2, -7) then the midpoint is at (2, -1.5)
7 APEX:)
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