It is the straight line joining the two points, A and B.
To find the length of the line segment with endpoints (7, 2) and (-4, 2), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Substituting the coordinates, we have (d = \sqrt{((-4) - 7)^2 + (2 - 2)^2} = \sqrt{(-11)^2 + 0^2} = \sqrt{121} = 11). Thus, the length of the line segment is 11 units.
(0.5, 2)
Points: (2, 3) and (4, 7) Gradient or slope: change in y/change in x = (7-3)/(4-2) = 4/2 = 2
7
15
The midpoint of the line segment of (7, 2) and (2, 4) is at (4.5, 3)
The midpoint of the line segment of (-4, -3) and (7, -5) is at (1.5, -4)
If you mean that the line segment endpoints are (-4, 0) and (7, 0) then the midpoint is (1.5, 0)
To find the length of the line segment with endpoints (7, 2) and (-4, 2), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Substituting the coordinates, we have (d = \sqrt{((-4) - 7)^2 + (2 - 2)^2} = \sqrt{(-11)^2 + 0^2} = \sqrt{121} = 11). Thus, the length of the line segment is 11 units.
(0.5, 2)
Points: (2, 3) and (4, 7) Gradient or slope: change in y/change in x = (7-3)/(4-2) = 4/2 = 2
no
Rain - 2011 Segment 7 2-4 was released on: USA: 17 May 2013
13
7
The midpoint of the line segment from ( 3, 7 ) to ( 8, 2 ) is at ( 5.5, 4.5 )
(6, −4)