To determine the magnitude of the force on a charge of (4Q), we need to know the arrangement of other charges and their distances from the (4Q) charge. The force can be calculated using Coulomb's law, which states that the force (F) between two point charges is given by (F = k \frac{|q_1 q_2|}{r^2}), where (k) is Coulomb's constant, (q_1) and (q_2) are the magnitudes of the charges, and (r) is the distance between them. Without specific values for the surrounding charges and their distances, we cannot provide a numerical answer.
If 12p + 4q = 55, then p = (55 - 4q)/12
3 -4q = 10q + 10 3 - 10 = 10q + 4q -7 = 14q q = -1/2
Do you mean: r = (4q-5p)/9? If so then: p = (9r-4q)/-5
Four quarters in a football game
i think its 4q
If 12p + 4q = 55, then p = (55 - 4q)/12
4q + 1 = 15 4q = 16 q = 4
3 -4q = 10q + 10 3 - 10 = 10q + 4q -7 = 14q q = -1/2
The given expression when simplified is: 5 -2q
It is: 10q-2060 when simplified.
12q - 4q = 8
(3*5)+(4*-2) = 7
You'd have no problem at all if it was [ 26 pigs + 1 quart + 1 rat + 4 quarts + 5 rats ]. You'd add up the quarts, and then you'd add up the rats. You do the same with p's, q's, and r's . 26p + q + r + 4q + 5r = 26p + 5q + 6r
Do you mean: r = (4q-5p)/9? If so then: p = (9r-4q)/-5
If you mean: -6q+7-2+4q then it is 5-2q when simplified
It's slang for "F&*k you."
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