In a beam or length of material, we generally consider the longitudinal axis as the major axis for bending. But torsion will bend the material from the vertical, will twist it around that longitudinal axis. And lateral forces will bend the material across it axis of latitude.
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X-4^2/5^ + Y+^2/6^2 = 1
The standard equation for an ellipse centered at the origin is [x2/a2] +[y2/b2] = 1If a > b then the major axis is horizontal. Where b > a then the major axis is vertical. Note : If a = b then the curve is a circle.When a > b then the minor axis is of length 2b (and the major axis is of length 2a).Hope this helps as it is not clear just what your question is.
The same as the major axis.
major axis
The square root of ( a squared plus b squared ), quantity divided by a, where a is the length of the semi-major axis and b is the length of the semi-minor axis.
The square root of ( a squared plus b squared ), quantity divided by a, where a is the length of the semi-major axis and b is the length of the semi-minor axis.
An oval,or more technically an ellipse, has a long ( major) axis and short (minor axis). If major axis length is a and minor length is b, then area, A is A = pi x a x b /4 where pi = 3.14 (approx)
In a beam or length of material, we generally consider the longitudinal axis as the major axis for bending. But torsion will bend the material from the vertical, will twist it around that longitudinal axis. And lateral forces will bend the material across it axis of latitude.
It could be many shapes: for example, an ellipse with a semi major axis of length 11 and semi minor axis of length 10.
The square root of ( a squared plus b squared ), quantity divided by a, where a is the length of the semi-major axis and b is the length of the semi-minor axis.
eccentricity = distance between foci ________________ length of major axis
pi*a*b where a = half length of major axis (horizontal) and b = half length of minor axis (vertical)
An oval, or more technically an ellipse, has a long ( major) axis and short (minor axis). If major axis length is a and minor length is b, then area, A is A = pi*a*b /4 where and so the area of half an oval is pi*a*b/8
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