There is no possible value of x that will satisfy the given equation. There is no possible value of x that will satisfy the given equation. There is no possible value of x that will satisfy the given equation. There is no possible value of x that will satisfy the given equation.
To the maximum degree of accuracy possible, it is 6811.
A minimum refers to the smallest possible value or quantity in a set or range, while a maximum refers to the largest possible value or quantity in a set or range. So, a minimum is less or smaller than a maximum.
The only variable on the right hand side is sin(x). The maximum value of sin(x) is 1. So, the max value of 3sin(x) is 3*1 = 3 and so, the max value of 3sin(x) + 2 is 3+2 = 5.
On the y-axis, normally.
The class interval is the maximum possible value in the class less the maximum possible value in the class below. The second is equivalent to the minimum possible value in the class.
Both the function "cos x" and the function "sin x" have a maximum value of 1, and a minimum value of -1.
There is no possible value of x that will satisfy the given equation. There is no possible value of x that will satisfy the given equation. There is no possible value of x that will satisfy the given equation. There is no possible value of x that will satisfy the given equation.
Assuming the standard x and y axes, the range is the maximum value of y minus minimum value of y; and the domain is the maximum value of x minus minimum value of x.
Sin(x) has a maximum value of +1 and a minimum value of -1.
To the maximum degree of accuracy possible, it is 6811.
1
The maximum value for m in a 3d orbital is 2. This corresponds to the three possible orientations of the orbital along the x, y, and z axes.
A minimum refers to the smallest possible value or quantity in a set or range, while a maximum refers to the largest possible value or quantity in a set or range. So, a minimum is less or smaller than a maximum.
The only variable on the right hand side is sin(x). The maximum value of sin(x) is 1. So, the max value of 3sin(x) is 3*1 = 3 and so, the max value of 3sin(x) + 2 is 3+2 = 5.
In Calculus, to find the maximum and minimum value, you first take the derivative of the function then find the zeroes or the roots of it. Once you have the roots, you can just simply plug in the x value to the original function where y is the maximum or minimum value. To know if its a maximum or minimum value, simply do your number line to check. the x and y are now your max/min points/ coordinates.
On the y-axis, normally.