To find the maximum value of (2x + 2y) in the feasible region, you typically need to identify the constraints that define this region, often in the form of inequalities. Then, you would evaluate the objective function at the vertices of the feasible region, which are the points of intersection of the constraints. The maximum value will be found at one of these vertices. If you provide the specific constraints, I can help you calculate the maximum value.
To find the maximum value of 2x + 5y within the feasible region, you would need to evaluate the objective function at each corner point of the feasible region. The corner points are the vertices of the feasible region where the constraints intersect. Calculate the value of 2x + 5y at each corner point and identify the point where it is maximized. This point will give you the maximum value of 2x + 5y within the feasible region.
To find the minimum value of (2x + 2y) in a feasible region, you typically need to know the constraints that define that region. If you have a specific set of inequalities or constraints, you can apply methods like the corner point theorem or linear programming techniques to evaluate the objective function at the vertices of the feasible region. Without specific constraints, it's impossible to determine the minimum value accurately. If you provide the constraints, I can assist you further in finding the minimum.
To find the maximum value of the function (p = 2x + 3y) within a given feasibility region, you would typically evaluate the function at the vertices of the region, as the maximum occurs at one of these points. First, identify the coordinates of the vertices from the feasibility region's constraints. Then, substitute these coordinates into the function (p) to determine which vertex yields the highest value. The maximum value will be the largest result obtained from these calculations.
To maximize ( x^3y^4 ) given the constraint ( 2x + 3y = 7 ) and ( x \geq 0, y \geq 0 ), we can use the method of Lagrange multipliers or substitute ( y ) in terms of ( x ). From the equation, express ( y ) as ( y = \frac{7 - 2x}{3} ). Substituting this into ( x^3y^4 ) will yield a function of ( x ) that can be maximized within the feasible region defined by the constraints. Solving this will give the maximum value of ( x^3y^4 ).
f(-2,3) = 11 f(5,-3) = -5 f(1,4) = 22, maximum
14
The answer obviously depends on what the boundaries of the feasibility region are.
To find the maximum value of 2x + 5y within the feasible region, you would need to evaluate the objective function at each corner point of the feasible region. The corner points are the vertices of the feasible region where the constraints intersect. Calculate the value of 2x + 5y at each corner point and identify the point where it is maximized. This point will give you the maximum value of 2x + 5y within the feasible region.
2x+2y
To find the minimum value of (2x + 2y) in a feasible region, you typically need to know the constraints that define that region. If you have a specific set of inequalities or constraints, you can apply methods like the corner point theorem or linear programming techniques to evaluate the objective function at the vertices of the feasible region. Without specific constraints, it's impossible to determine the minimum value accurately. If you provide the constraints, I can assist you further in finding the minimum.
5
To find the maximum value of the function (p = 2x + 3y) within a given feasibility region, you would typically evaluate the function at the vertices of the region, as the maximum occurs at one of these points. First, identify the coordinates of the vertices from the feasibility region's constraints. Then, substitute these coordinates into the function (p) to determine which vertex yields the highest value. The maximum value will be the largest result obtained from these calculations.
To maximize ( x^3y^4 ) given the constraint ( 2x + 3y = 7 ) and ( x \geq 0, y \geq 0 ), we can use the method of Lagrange multipliers or substitute ( y ) in terms of ( x ). From the equation, express ( y ) as ( y = \frac{7 - 2x}{3} ). Substituting this into ( x^3y^4 ) will yield a function of ( x ) that can be maximized within the feasible region defined by the constraints. Solving this will give the maximum value of ( x^3y^4 ).
f(-2,3) = 11 f(5,-3) = -5 f(1,4) = 22, maximum
sin(theta) reach a maximum at pi / 2 + all even multiple of 2 pi. As a result, the smallest positive value of x where y = sin(2x) is maximal is pi / 2.
18
If you mean 2x = 28 then the value of x is 14